PAT (Advanced Level) 1107. Social Clusters (30)

时间:2023-03-09 08:54:18
PAT (Advanced Level) 1107. Social Clusters (30)

简单并查集。

#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#include<map>
#include<queue>
#include<stack>
#include<algorithm>
using namespace std; const int maxn=+;
int fa[maxn];
int num[maxn];
int n;
vector<int>g[maxn],ans; int f(int x)
{
if(x!=fa[x]) fa[x]=f(fa[x]);
return fa[x];
} int main()
{
scanf("%d",&n);
for(int i=;i<=n;i++)
{
int num; scanf("%d:",&num);
while(num--)
{
int hob; scanf("%d",&hob);
g[hob].push_back(i);
}
} for(int i=;i<=n;i++) fa[i]=i; for(int i=;i<=;i++)
{
if(g[i].size()==) continue;
int u=f(g[i][]);
for(int j=;j<g[i].size();j++)
{
int v=f(g[i][j]);
if(u!=v) fa[v]=u;
}
} for(int i=;i<=n;i++) f(i); memset(num,,sizeof num);
for(int i=;i<=n;i++) num[f(i)]++;
for(int i=;i<=n;i++) if(num[i]>) ans.push_back(num[i]); sort(ans.begin(),ans.end());
printf("%d\n",ans.size());
for(int i=ans.size()-;i>=;i--)
{
printf("%d",ans[i]);
if(i>) printf(" ");
else printf("\n");
} return ;
}