Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
For example, this binary tree is symmetric:
1
/ \
2 2
/ \ / \
3 4 4 3
But the following is not:
1
/ \
2 2
\ \
3 3
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean isSymmetric(TreeNode root) {
return isSymmetric(root,root);
}
public boolean isSymmetric(TreeNode t1,TreeNode t2) {
if(t1==null && t2==null) return true;
if(t1==null || t2==null) return false;
return(t1.val==t2.val && isSymmetric(t1.left,t2.right) && isSymmetric(t1.right,t2.left));
}
}