Tree View 指令不支持 树结构数据源， 只支持单层数组。（也许是我没发现，人家可以设置） 。我只能把树展开，变成单层数组。然后还要记录已经递归到第一层了。比如这样。
<!doctype html>
<html lang="en-US">
<head>
<meta charset="UTF-8">
<title></title>
</head>
<body>
<script type="text/javascript">
var self = this;
self.list = [
{
"id": 1,
"title": "node1",
"children": [
{
"id": 11,
"title": "node1.1",
"children": [
{
"id": 111,
"title": "node1.1.1"
}
]
},
{
"id": 12,
"title": "node1.2",
"children": []
}
]
},
{
"id": 2,
"title": "node2",
"nodrop": true,
"children": [
{
"id": 21,
"title": "node2.1",
"children": []
},
{
"id": 22,
"title": "node2.2",
"children": []
}
]
},
{
"id": 3,
"title": "node3",
"children": [
{
"id": 31,
"title": "node3.1",
"children": []
}
]
}
];
function flatten (arr,level){
var result = [],
recursion = function (arr,level) {
arr.level = arr.level || level || 0;
//这里用了个巧妙的方法，记录该数组的level。有就用它自己的，没有就判断是不是别人给它的，别人给的一般代表自己是子树。然后给的时候 +1
arr.forEach(function (item) {
item.$$treeLevel = arr.level;
result.push(item);
item.children && recursion(item.children,arr.level + 1);
});
delete arr.level;
};
recursion(arr);
return result;
};
self.arr = flatten(self.list);
console.log(self.arr);
</script>
</body>
</html>
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