C语言回调函数总结

时间:2023-03-10 07:19:29
C语言回调函数总结
/*
Main program ---calls--> Library function ---calls--> Callback funtion
*/
#include <stdio.h>
#include <stdlib.h> typedef double (*op_fun)(double, double);/*函数指针的第一种定义方式,比较奇怪为什么不是 double () (double, double) * op_fun; 这种形式。*/ typedef struct _OP
{
double (*add)(double, double); /*函数指针第二种定义方式*/
double (*sub)(double, double);
double (*mul)(double, double);
//double (*div)(double, double);
op_fun div;
} OP; double add(double a, double b)
{
return a + b;
} double sub(double a, double b)
{
return a - b;
} double mul(double a, double b)
{
return a * b;
} double div(double a, double b)
{
return a / b;
} void OP_init(OP * op)
{
op->add = add;
op->sub = sub; /*函数指针第一种赋值方式*/
op->mul = &mul; /*函数指针第二种赋值方式*/
op->div = &div;
} /*Library function*/
double lib_fun(double a, double b, double (*op)(double, double))
{
return op(a, b);
//return (*op)(a, b);
} //double (*op_arr[5])(double, double); /*声明函数指针数组的第一种方式*/
op_fun op_arr[]; /*声明函数指针数组的第二种方式*/ void op_arr_init() {
op_arr[] = add;
op_arr[] = sub;
op_arr[] = &mul;
op_arr[] = &div;
} double (* get_op(int num))(double, double) /*函数指针作为返回值,get_op参数为(int num),返回类型为double(*)(double, double)*/
{
op_arr_init();
if ( <= num && num <= ) return op_arr[num];
return NULL;
} int main(int argc, char const *argv[])
{
OP * op = (OP *)malloc(sizeof(OP));
OP_init(op);
double a, b;
scanf("%lf %lf", &a, &b);
printf("ADD = %lf, SUB = %lf, MUL = %lf, DIV = %lf\n", (op->add)(a, b), (op->sub)(a, b), /*函数指针第一种调用方式*/
(*op->mul)(a, b), (*op->div)(a, b)); /*函数指针第二种调用方式*/
printf("ADD = %lf, SUB = %lf, MUL = %lf, DIV = %lf\n", lib_fun(a, b, add), lib_fun(a, b, sub), lib_fun(a, b, mul), lib_fun(a, b, div));
free(op); int num;
printf("Input operation(1:add, 2:sub, 3:mul, 4:div):\n");
scanf("%d", &num);
if (num) printf("Answer is %lf\n", lib_fun(a, b, get_op(num)));
else printf("Wrong!\n");
return ;
}