HDU-5391 Zball in Tina Town

时间:2023-03-08 16:29:41
HDU-5391 Zball in Tina Town

(n-1)!/n 就是如果n为素数,就等于n-1else为0。

求素数表:

Zball in Tina Town

Time Limit: 3000/1500 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)
Total Submission(s): 833 Accepted Submission(s):
477

Problem Description
Tina Town is a friendly place. People there care about
each other.

Tina has a ball called zball. Zball is magic. It grows larger
every day. On the first day, it becomes 1HDU-5391 Zball in Tina Town

time as large as its original size. On the second day,it will become 2HDU-5391 Zball in Tina Town

times as large as the size on the first day. On the n-th day,it will become
nHDU-5391 Zball in Tina Town

times as large as the size on the (n-1)-th day. Tina want to know its size on
the (n-1)-th day modulo n.

Input
The first line of input contains an integer THDU-5391 Zball in Tina Town

, representing the number of cases.

The following THDU-5391 Zball in Tina Town

lines, each line contains an integer nHDU-5391 Zball in Tina Town

, according to the description.
T≤10HDU-5391 Zball in Tina Town5HDU-5391 Zball in Tina Town,2≤n≤10HDU-5391 Zball in Tina Town9HDU-5391 Zball in Tina TownHDU-5391 Zball in Tina Town

Output
For each test case, output an integer representing the
answer.
Sample Input
2
3
10
Sample Output
2
0
Source
#include<iostream>
#include <cstdio>
#include<cstring>
using namespace std;
bool is_prime(int n)
{
for(int i=;i*i<=n;i++){
if(n%i==) return false;
}
return n!=;
}
int main (void)
{
int n,t;
scanf("%d",&t);
while(t--)
{
scanf("%d",&n);
if(n==)
{
printf("2\n");
continue;
}
if(is_prime(n))
printf("%d\n",n-);
else
printf("0\n"); }
return ;
}