836. Rectangle Overlap时间:2023-03-09 21:24:14 class Solution { public: bool isRectangleOverlap(vector<int>& rec1, vector<int>& rec2) { return rec1[]<rec2[]&&rec2[]<rec1[]&&rec1[]<rec2[]&&rec2[]<rec1[]; } }; r1left r2left r1right r2right 一个方向上的判定条件:left1<right2&&left2<right1 用两个方向上的判定即可