#include <iostream>
#include <fstream> using namespace std; int main()
{ char s[27],m[27];
int a[27];
int i,j,sum; ifstream infile1,infile2; //定义输入文件
ofstream outfile; //定义输出文件
infile1.open("file1.txt");
infile2.open("file2.txt");
outfile.open("file3.txt"); for (i=0; i<26; i++)
{
infile1>>s[i]; } for (i=0; i<26; i++)
{
infile2>>a[i];
} cout<<"输入"<<endl;
for (j=0; j<18; j++)
{
cin>>m[j];
for (i=0; i<26; i++)
{
if (s[i]==m[j])
{
sum+=a[i]; }
}
}
cout<<sum<<endl;
outfile<<sum; infile1.close();
infile2.close();
outfile.close(); }
如果令A,B,C,D,……,X,Y,Z这26个英文字母,分别等于百分之1,2,……,24,25,26个数值,那么我们就能得出如下有趣的结论:
HARD WORD 8+1+18+4+23+15+18+11=98%
KNOWLEDGE 96%
LOVE 54% LUCK 47%
计算一下MONEY STUDY ATTITUDE