Codeforces Round #244 (Div. 2) A. Police Recruits时间:2023-03-08 22:58:32 题目的意思就是找出未能及时处理的犯罪数, #include <iostream> using namespace std; int main(){ int n; cin >> n; int a,recruit = , crimes = ;; for(int i = ; i < n; ++ i){ cin >> a; if(a > ) recruit+=a; else recruit?recruit-- : crimes++; } cout<<crimes<<endl; }