bzoj4445(半平面交)

时间:2023-03-08 22:15:55

列出式子对一下然后上半平面交

#include<iostream>
#include<cstring>
#include<cmath>
#include<cstdio>
#include<algorithm>
using namespace std;
const int maxn=;
const double eps=1e-;
int n,m;
int head,tail;
struct vec{
double x,y;
vec(double x=,double y=):x(x),y(y){}
vec operator-(vec& a){
return vec(x-a.x,y-a.y);
}
vec operator+(vec&a){
return vec(x+a.x,y+a.y);
}
}po[maxn],g[maxn],tmp;
vec operator*(vec a,double t){return vec(a.x*t,a.y*t);}
double cross(vec a,vec b){return a.x*b.y-b.x*a.y;}
struct lin{
vec p,v;
double ang;
lin(){}
lin(vec p,vec v):p(p),v(v){ang=atan2(v.y,v.x);}
bool operator<(const lin&a)const{
return ang<a.ang;
}
}ll[maxn],q[maxn];
bool onl(lin L,vec p){
return cross(L.v,p-L.p)>;
}
vec qj(lin a,lin b){
vec u=a.p-b.p;
double t=cross(b.v,u)/cross(a.v,b.v);
return a.v*t+a.p;
}
int halfj(){
sort(ll,ll+n);
//int head,tail;
q[head=tail=]=ll[];
for(int i=;i<n;++i){
while(head<tail&&!onl(ll[i],g[tail-]))tail--;
while(head<tail&&!onl(ll[i],g[head]))head++;
q[++tail]=ll[i];
if(fabs(cross(q[tail].v,q[tail-].v))<eps){
--tail;if(onl(q[tail],ll[i].p))q[tail]=ll[i];
}
if(head<tail)g[tail-]=qj(q[tail-],q[tail]);
}
while(head<tail&&!onl(q[head],g[tail-]))--tail;
g[tail]=qj(q[head],q[tail]);++tail;
}/*
void halfj(){
sort(ll,ll+n);
//for(int i=0;i<n;++i)cout<<ll[i].p.x<<' '<<ll[i].p.y<<' '<<ll[i].v.x<<' '<<ll[i].v.y<<endl;
q[head=tail=0]=ll[0];
for(int i=1;i<n;++i){
while(head<tail&&!onl(ll[i],g[tail-1]))tail--;
while(head<tail&&!onl(ll[i],g[head]))head++;
q[++tail]=ll[i];
if(fabs(cross(q[tail].v,q[tail-1].v))<eps){
--tail;if(onl(q[tail],ll[i].p))q[tail]=ll[i];
}
if(head<tail)g[tail-1]=qj(q[tail-1],q[tail]);
}
while(head<tail&&!onl(q[head],g[tail-1]))--tail;
}*/
void add(int i,int j){
double a=po[].y-po[i].y-po[].y+po[j].y;
double b=po[].x-po[j].x-po[].x+po[i].x;
double c=cross(po[],po[])-cross(po[i],po[j]);
tmp.x=b?:-c/a;
tmp.y=b?-c/b:;
ll[i]=lin(tmp,vec(-b,a));
}
double are(vec *p,int n){
double sum=cross(p[n-],p[]);
for(int i=;i<n;++i){
sum+=cross(p[i-],p[i]);
}
return sum;
}
int main(){
cin>>n;
for(int i=;i<n;++i){
scanf("%lf%lf",&po[i].x,&po[i].y);
}
ll[]=lin(po[],po[]-po[]);
for(int i=;i<n;++i)add(i,(i+)%n);
halfj();
printf("%.4lf\n",are(g,tail)/are(po,n));
return ;
}
/*
1 8 -1 -1
0 7 1 -6
0 0.777778 9 1
0 -57 1 9
0 8.16667 -6 1
*/