【 CodeForces 604A】B - 特别水的题2-Uncowed Forces

时间:2022-04-02 17:43:48

http://acm.hust.edu.cn/vjudge/contest/view.action?cid=102271#problem/B

Description

Kevin Sun has just finished competing in Codeforces Round #334! The round was 120 minutes long and featured five problems with maximum point values of 500, 1000, 1500, 2000, and 2500, respectively. Despite the challenging tasks, Kevin was uncowed and bulldozed through all of them, distinguishing himself from the herd as the best cowmputer scientist in all of Bovinia. Kevin knows his submission time for each problem, the number of wrong submissions that he made on each problem, and his total numbers of successful and unsuccessful hacks. Because Codeforces scoring is complicated, Kevin wants you to write a program to compute his final score.

Codeforces scores are computed as follows: If the maximum point value of a problem is x, and Kevin submitted correctly at minute mbut made w wrong submissions, then his score on that problem is 【 CodeForces 604A】B - 特别水的题2-Uncowed Forces. His total score is equal to the sum of his scores for each problem. In addition, Kevin's total score gets increased by 100 points for each successful hack, but gets decreased by 50 points for each unsuccessful hack.

All arithmetic operations are performed with absolute precision and no rounding. It is guaranteed that Kevin's final score is an integer.

Input

The first line of the input contains five space-separated integers m1m2m3m4m5, where mi (0 ≤ mi ≤ 119) is the time of Kevin's last submission for problem i. His last submission is always correct and gets accepted.

The second line contains five space-separated integers w1w2w3w4w5, where wi (0 ≤ wi ≤ 10) is Kevin's number of wrong submissions on problem i.

The last line contains two space-separated integers hs and hu (0 ≤ hs, hu ≤ 20), denoting the Kevin's numbers of successful and unsuccessful hacks, respectively.

Output

Print a single integer, the value of Kevin's final score.

Sample Input

Input

20 40 60 80 100
0 1 2 3 4
1 0

Output

4900

Input

119 119 119 119 119
0 0 0 0 0
10 0

Output

4930

Hint

In the second sample, Kevin takes 119 minutes on all of the problems. Therefore, he gets 【 CodeForces 604A】B - 特别水的题2-Uncowed Forces of the points on each problem. So his score from solving problems is【 CodeForces 604A】B - 特别水的题2-Uncowed Forces. Adding in 10·100 = 1000points from hacks, his total score becomes 3930 + 1000 = 4930.

简单模拟。

#include<stdio.h>
#include<algorithm>
#define maxx 10
using namespace std;
long long hu,hs;
double x[maxx]={, , , , },w[maxx],score,m[maxx];
int main(){
for(int i=;i<;i++)
scanf("%lf",&m[i]);
for(int i=;i<;i++)
scanf("%lf",&w[i]);
scanf("%lld%lld",&hs,&hu);
for(int i=;i<;i++)
score+=max(0.3*x[i],(-m[i]/)*x[i]-*w[i]);
score+=*hs-*hu;
printf("%.0f\n",score);//.0f实际上是四舍五入,但是题目保证了答案一定是整数
return ;
}

或者

#include<stdio.h>
#include<algorithm>
#define maxx 10
using namespace std;
long long x[maxx]={, , , ,},w[maxx],score,m[maxx],hu,hs;
int main(){
for(int i=;i<;i++)
scanf("%lld",&m[i]);
for(int i=;i<;i++)
scanf("%ldd",&w[i]);
scanf("%lld%lld",&hs,&hu);
for(int i=;i<;i++)
score+=max(x[i]*/,(x[i]-m[i]*x[i]/)-*w[i]);
score+=*hs-*hu;
printf("%lld\n",score);
return ;
}