A - Anton and Polyhedrons
题目连接：
http://codeforces.com/contest/785/problem/A
Description
Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
Tetrahedron. Tetrahedron has 4 triangular faces.
Cube. Cube has 6 square faces.
Octahedron. Octahedron has 8 triangular faces.
Dodecahedron. Dodecahedron has 12 pentagonal faces.
Icosahedron. Icosahedron has 20 triangular faces.
All five kinds of polyhedrons are shown on the picture below:
Anton has a collection of n polyhedrons. One day he decided to know, how many faces his polyhedrons have in total. Help Anton and find this number!
Input
The first line of the input contains a single integer n (1 ≤ n ≤ 200 000) — the number of polyhedrons in Anton's collection.
Each of the following n lines of the input contains a string si — the name of the i-th polyhedron in Anton's collection. The string can look like this:
"Tetrahedron" (without quotes), if the i-th polyhedron in Anton's collection is a tetrahedron.
"Cube" (without quotes), if the i-th polyhedron in Anton's collection is a cube.
"Octahedron" (without quotes), if the i-th polyhedron in Anton's collection is an octahedron.
"Dodecahedron" (without quotes), if the i-th polyhedron in Anton's collection is a dodecahedron.
"Icosahedron" (without quotes), if the i-th polyhedron in Anton's collection is an icosahedron.
Output
Output one number — the total number of faces in all the polyhedrons in Anton's collection.
Sample Input
4
Icosahedron
Cube
Tetrahedron
Dodecahedron
Sample Output
42
Hint
题意
给你一堆多面体，然后问你总共多少个面。
题解：
实际上只需要if if if if就好了嘛
代码
#include<bits/stdc++.h>
using namespace std;
int n,ans=0;
string s;
int main(){
cin>>n;
for(int i=0;i<n;i++){
cin>>s;
if(s=="Tetrahedron")ans+=4;
if(s=="Cube")ans+=6;
if(s=="Octahedron")ans+=8;
if(s=="Dodecahedron")ans+=12;
if(s=="Icosahedron")ans+=20;
}
cout<<ans<<endl;
}