luogu2596 [ZJOI2006]书架

时间:2023-03-10 05:49:48
luogu2596 [ZJOI2006]书架

treap。树是以“优先级”(优先级越小,在书架上越靠上)形成的,堆是以rand()的权值形成的。还要再维护一个原编号。

置顶/置底:找到那个元素,把它拉出来修改优先级再塞回去。

insert:即一个元素和他“附近”的元素交换位置,把他们两个拉出来,交换优先级再塞回去

#include <iostream>
#include <cstdlib>
#include <cstdio>
using namespace std;
int n, m, minn, maxn, a[80005], uu, rot, vv, cnt;
char ss[15];
struct Treap{
int val[200005], rnd[200005], l[200005], r[200005], siz[200005];
int bh[200005];
void upd(int x){
siz[x] = siz[l[x]] + siz[r[x]] + 1;
}
void lRotate(int &k){
int t=r[k]; r[k] = l[t]; l[t] = k;
siz[t] = siz[k]; upd(k); k = t;
}
void rRotate(int &k){
int t=l[k]; l[k] = r[t]; r[t] = k;
siz[t] = siz[k]; upd(k); k = t;
}
void insert(int &k, int b){
if(!k){
k = ++cnt; val[k] = a[b]; bh[k] = b;
rnd[k] = rand(); siz[k] = 1;
return ;
}
siz[k]++;
if(val[k]<a[b]){
insert(r[k], b);
if(rnd[r[k]]<rnd[k]) lRotate(k);
}
else{
insert(l[k], b);
if(rnd[l[k]]<rnd[k]) rRotate(k);
}
}
void shanchu(int &k, int b){
if(!k) return ;
if(val[k]==a[b]){
if(l[k]*r[k]==0) k = l[k] + r[k];
else if(rnd[l[k]]<rnd[r[k]])
rRotate(k), shanchu(k, b);
else
lRotate(k), shanchu(k, b);
}
else if(val[k]>a[b])
siz[k]--, shanchu(l[k], b);
else
siz[k]--, shanchu(r[k], b);
}
int queryRank(int k, int b){
if(!k) return 0;
if(a[b]<val[k]) return queryRank(l[k], b);
else if(a[b]>val[k]) return queryRank(r[k], b)+siz[l[k]]+1;
else return siz[l[k]]+1;
}
int queryNum(int k, int b){
if(!k) return 0;
if(b<=siz[l[k]]) return queryNum(l[k], b);
else if(b>siz[l[k]]+1) return queryNum(r[k], b-siz[l[k]]-1);
else return bh[k];
}
}treap;
int main(){
cin>>n>>m;
minn = 1; maxn = n;
for(int i=1; i<=n; i++){
scanf("%d", &uu);
a[uu] = i;
treap.insert(rot, uu);
}
while(m--){
scanf("%s %d", ss, &uu);
if(ss[0]=='T'){
treap.shanchu(rot, uu);
a[uu] = --minn;
treap.insert(rot, uu);
}
if(ss[0]=='B'){
treap.shanchu(rot, uu);
a[uu] = ++maxn;
treap.insert(rot, uu);
}
if(ss[0]=='I'){
scanf("%d", &vv);
if(vv==0) continue;
int t=treap.queryRank(rot, uu);
int q=treap.queryNum(rot, t+vv);
treap.shanchu(rot, uu);
treap.shanchu(rot, q);
swap(a[uu], a[q]);
treap.insert(rot, uu);
treap.insert(rot, q);
}
if(ss[0]=='A')
printf("%d\n", treap.queryRank(rot, uu)-1);
if(ss[0]=='Q')
printf("%d\n", treap.queryNum(rot, uu));
}
return 0;
}