有一张表test如下：
create table test
(
id int identity(1,1) primary key,
num int
)
插入数据：
insert into test( num) values (1);
insert into test( num) values (2);
insert into test( num) values (8);
insert into test( num) values (15);
insert into test( num) values (12);
insert into test( num) values (13);
insert into test( num) values (14);
insert into test( num) values (16);
insert into test( num) values (17);
insert into test( num) values (5);
insert into test( num) values (6);
insert into test( num) values (7);
insert into test( num) values (16);
insert into test( num) values (18);
insert into test( num) values (9);
insert into test( num) values (10);
insert into test( num) values (11);
insert into test( num) values (12);
insert into test( num) values (19);
insert into test( num) values (20);
insert into test( num) values (3);
insert into test( num) values (4);
insert into test( num) values (19);
insert into test( num) values (20);
insert into test( num) values (17);
insert into test( num) values (18);
问题：请用一条sql语句查询 统计出num在 1~6, 10~17, 19~20 这三个范围内的个数分别是多少？
解法如下：
select
COUNT (case when num between 1 and 6 then 1 end ) as [1-6],
COUNT( case when num between 10 and 17 then 2 end ) as [10-17],
COUNT (case when num between 19 and 20 then 3 end ) as [19-20]
from test
如果问题是问1~5, 6~10,11~15这样成倍数(有规律)的话，则可以这样写：
select COUNT(*) from test group by num/5