[转]SQL 常用函数及示例

时间:2023-03-08 17:24:35

原文地址:http://www.cnblogs.com/canyangfeixue/archive/2013/07/21/3203588.html

--SQL 基础-->常用函数

--==================================

/*

一、函数的分类

SQL函数一般分为两种

单行函数 基于单行的处理,一行产生一个结果

多行函数 基于多行的处理,对多行进行汇总,多行产生结果

二、函数形式

function_name [(arg1, arg2,...)]

三、常用的单行函数:

1. 字符函数:

lower(x)   转小写

upper(x)   转大写

initcap(x) 单词首字母转大写

concat(x,y)   字符连接与| | 功能类似

substr(x,start [,length])   取子串

格式: substr('asdfasdfasdfasddf',1,3)

length(x)  取字符串长度

lpad | rpad(x,width [,pad_string]) 字符定长,(不够长度时,左|右填充)

trim([trim_charFROM] x)  删除首部、尾部字符

格式:trim('h' from 'hello hello')

trim 默认删除方式是both

leading   只删首部   trim(leading 'h' from 'hello helloh')

trailing  只删尾部   trim(trailing 'h' from 'hello helloh')

ltrim(x[,trim_string])  从x右边删除字符  等价于使用trailing

rtrim(x[,trim_string])  从x左边删除字符  等价于使用leading

instr   返回子字符串在字符串中的位置

格式:instr(string,substring,position,occurence)

replace(x,search_string,replace_string)   字符替换

格式:replace('字符', '字符' ,'字符')

将字符中的字符,替换成字符

2.  数值函数:

round(x [,y])      四舍五入

trunc(x,[,y])       截断

mod(m,n)            求余

ceil(x)                 返回特定的最小数(大于等于x的最小整数)

floor(x)            返回特定的最大数(小于等于x的最大整数)

3.  日期函数:

sysdate    返回系统当前日期

实际上ORACLE内部存储日期的格式是:世纪,年,月,日,小,分钟,秒。

不管如何输入都这样

9i开始,默认的日期格式是:DD-MON-RR,之前是DD-MON-YY

RR 和YY 都是世纪后的两位,但有区别

ORACLE的有效日期范围是:公元前年月日-年月日

RR日期格式:

1、如果当前年份最后两位是:-,并且指定年份的最后两位也为-,

则返回本世纪

例:当前年:, 01--,表示2008 年

2、如果当前年份最后两位是:-,指定年份最后两位为50-

则返回上世纪。

例:当前年:,01--,表示1998

3、如果当前年最后两位为:-,指定年份最后两位为0-,

则返回下世纪。

例:当前年:,--表示的是年

4、如果当前年最后两位是:-,指定年份最后两位为:-

则返回本世纪。

例:当前年:,--表示的是年

months_between(x,y) 两个日期之间相差的月数

例:查询最近个月入职的员工

add_months(x,y)      返回x上加上y个月后的结果

last_day(x)           返回指定日期所在月最后一天的日期

next_day(x,day)    返回指定日期的下一day的时间值,day是一个文本串,比如SATURDAY

extract       提取日期

select extract(day from sysdate) from dual

select extract(month from sysdate) from dual;

select extract(year from sysdate) from dual;

4.  转换函数:

TO_DATE(char[, 'format_model']) TO_DATE函数将一个字符串转换成日期格式

函数有个fx 修饰语。这个修饰语为TO_DATE函数的字符函

数中的独立变量和日期格式指定精确匹配.

TO_CHAR(date, 'format_model')   转换为CHAR类型,

必须与单引号一起嵌入,区分大小写,

用逗号把日期数值分开,有一个fm 移除填补空白或者阻止零开头

TO_CHAR(number, 'format_model')

TO_NUMBER(char[, 'format_model'])  TO_NUMBER 函数将一个字符串转换成一个数字格式:

select to_date('1999-09-23','yyyy-mm-dd') from dual;

数据类型的转换分为隐式数据类型转换和显式数据类型转换

在表达式中, Oracle服务器能自动地转换下列各项,即隐式转换:

VARCHAR2 or CHAR  =====〉NUMBER

VARCHAR2 or CHAR  =====〉DATE

对表达式赋值, Oracle服务器能自动地转换下列各项,即隐式转换:

NUMBER =======〉VARCHAR2 or CHAR

DATE   =======〉VARCHAR2 or CHAR

日期格式元素:

YYYY   数字年份

YEAR   英文年份

MM  数字月

MONTH  英文月

MON 英文缩写

DD  数字日

DY  英文缩写

DAY 英文

5.  通用函数

decode 条件判断

格式:decode (col|expression,search1,result1 [,search2,result2,...] [,default])

判断col|exporession的值,当search1匹配时,则返回,result1,

与search2匹配时,返回result2 ... 如果都不匹配,返回default。

select EMPNO,ENAME,JOB,SAL,

decode(job,'CLERK',SAL*1.15,'SALESMAN',SAL*1.1,SAL*1.12) NEW_SAL

FROM SCOTT.EMP;

if then else  条件判断

case 表达式

CASE expr WHEN comparison_expr1 THEN return_expr1

[WHEN comparison_expr2 THEN return_expr2

WHEN comparison_exprn THEN return_exprn

ELSE else_expr]

END

四、演示*/ 

--lower函数
SQL> select lower('SQL') from dual; LOW
---
sql SQL> select EMPNO,ENAME,JOB from scott.emp where lower(ename) like 'a%'; EMPNO ENAME JOB
---------- ---------- ---------
7499 ALLEN SALESMAN
7876 ADAMS CLERK SQL> insert into scott.emp(empno,ename) values(9999,'albert'); 1 row created. SQL> select * from scott.emp where lower(ename) like 'a%'; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- ---------- ---------- ---------- ----------
9999 albert
7499 ALLEN SALESMAN 7698 1981-02-20 1600 300 30
7876 ADAMS CLERK 7788 1987-05-23 1100 20 SQL> select * from scott.emp where ename like 'A%'; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- ---------- ---------- ---------- ----------
7499 ALLEN SALESMAN 7698 1981-02-20 1600 300 30
7876 ADAMS CLERK 7788 1987-05-23 1100 20 --upper函数
SQL> select upper('SQL Course') as Upper_Char from dual; UPPER_CHAR
----------
SQL COURSE --单词首子母转大写
SQL> select initcap(ename) as initcap_name scott.emp where ename = 'albert'; INITCAP_NAME
----------
Albert --字符的拼接,||与concat等效
SQL> select ename || ' is an ' || job from scott.emp where ename = 'SCOTT'; ENAME||'ISAN'||JOB
---------------------------
SCOTT is an ANALYST SQL> select concat(concat(ename,' is an '),job) as concat_str from scott.emp where ename = 'SCOTT'; CONCAT_STR
--------------------------
SCOTT is an ANALYST --SUBSTR,截取子串,下面的例子从第个位置开始连续截取个字符
SQL> select substr('HelloWorld',2,3) from dual; SUB
---
ell --LENGTH 取字符串长度
SQL> select length('HelloWord') as String_length from dual; STRING_LENGTH
-------------
9 -- lpad | rpad 字符串的填充
-- lpad,左填充,直到达到指定长度为止
SQL> select lpad('salary',10,'*') as String_Lpad from dual; STRING_LPA
----------
****salary --指定长度为,多出的部分被截断
SQL> select lpad('salary',4,'*') as String_Lpad from dual; STRI
----
sala --rpad,右填充,直到达到指定长度为止
SQL> select rpad('salary',10,'|') as String_Rpad from dual; STRING_RPA
----------
salary|||| --指定长度为,多出的部分被截断
SQL> select rpad('salary',5,'|') as String_Rpad from dual; STRIN
-----
salar -- trim 删除首尾字符,格式:trim('h' from 'hello hello'),默认的方式为both
SQL> select trim('h' from 'hello helloh') as String_Trim from dual; STRING_TRI
----------
ello hello -- trim 删除首尾字符,指定leading只删首部
SQL> select trim(leading 'h' from 'hello helloh') as Trim_Leading from dual; TRIM_LEADIN
-----------
ello helloh -- trim 删除首尾字符,指定trailing只删尾部
SQL> select trim(trailing 'h' from 'hello helloh') as Trim_Trailling from dual; TRIM_TRAILL
-----------
hello hello --rtrim ,ltrim
SQL> select rtrim('hello helloh','h') as Rtrim_String ,
2 ltrim('hello helloh','h') as Ltrim_String
3 from dual; RTRIM_STRIN LTRIM_STRIN
----------- -----------
hello hello ello helloh --replace 字符替换
SQL> select replace('Jack and Johnson','J','Bl') as String_Replace from dual; STRING_REPLACE
------------------
Black and Blohnson --instr 下面的示例从第个字符开始,返回第二个OR的位置
SQL> select instr('CORPORATE FOLLOR','OR',3,2) as Instring from dual; INSTRING
----------
15 --round 四舍五入函数
SQL> select round(102.253,2) as round_func from dual; ROUND_FUNC
----------
102.25 SQL> select round(102.253,0) as round_func from dual; ROUND_FUNC
----------
102 SQL> select round(102.253,-1) as round_func from dual; ROUND_FUNC
----------
100 --trunc 截断函数
SQL> select trunc(2010.328) as trunc_func_1,
2 trunc(2010.328,1) as trunc_func_2,
3 trunc(2010.328,-1) as trunc_func_3
4 from dual; TRUNC_FUNC_1 TRUNC_FUNC_2 TRUNC_FUNC_3
------------ ------------ ------------
2010 2010.3 2010 --#MOD(m,n) 取余函数
SQL> select mod(2010,3) as mod_func from dual; MOD_FUNC
----------
0 SQL> select mod(5,3) as mod_func from dual; MOD_FUNC
----------
2 --ceil(x) 返回特定的最小数(大于等于x的最小整数)
SQL> select ceil(593.3) as ceil_func from dual; CEIL_FUNC
----------
594 --floor(x) 返回特定的最大数(小于等于x的最大整数)
SQL> select floor(593.4) as floor_func from dual; FLOOR_FUNC
----------
593 --month_between(日期,日期)两个日期相差的月数
SQL> select empno,ename,job,months_between(sysdate,hiredate) as diff_month from scott.emp; EMPNO ENAME JOB DIFF_MONTH
---------- ---------- --------- ----------
9999 albert
7369 SMITH CLERK 351.370601
7499 ALLEN SALESMAN 349.273827
7521 WARD SALESMAN 349.209311
7566 JONES MANAGER 347.854472
7654 MARTIN SALESMAN 342
7698 BLAKE MANAGER 346.88673
7782 CLARK MANAGER 345.628666
7788 SCOTT ANALYST 275.306085
7839 KING PRESIDENT 340.370601
7844 TURNER SALESMAN 342.660924 SQL> select * from scott.emp where months_between(sysdate,hiredate) <= 300; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
---------- ---------- --------- ---------- ---------- ---------- ---------- ----------
7788 SCOTT ANALYST 7566 1987-04-19 3000 20
7876 ADAMS CLERK 7788 1987-05-23 1100 20 --add_months(日期,n) 返回在指定的日期后,加上n个月后的日期
SQL> select add_months(sysdate,5) from dual; ADD_MONTHS
----------
2010-08-28 --last_day(sysdate) 返回指定日期所在月最后一天的日期
SQL> select last_day(sysdate) from dual; LAST_DAY(S
----------
2010-03-31 --next_day 返回指定日期的下一day的时间值,day是一个文本串,比如SATURDAY
SQL> select next_day('05-FEB-2005','TUESDAY') as nextday from dual; NEXTDAY
---------
08-FEB-05 /*EXTRACT*/ SQL> select extract(day from sysdate) from dual; EXTRACT(DAYFROMSYSDATE)
-----------------------
28 SQL> select extract(month from sysdate) from dual; EXTRACT(MONTHFROMSYSDATE)
-------------------------
3 SQL> select extract(year from sysdate) from dual; EXTRACT(YEARFROMSYSDATE)
------------------------
2010 --使用ROUND 和TRUNC函数处理日期
--round(sysdate,'MONTH') 当月第一天
--round(sysdate,'YEAR') 当年的第一天
--trunc(sysdate,'MONTH') 当月第一天
--trunc(sysdate,'YEAR') 当年的第一天
SQL> select sysdate,round(sysdate,'MONTH'),round(sysdate,'YEAR'),
2 trunc(sysdate,'MONTH'),trunc(sysdate,'YEAR')
3 from dual; SYSDATE ROUND(SYS ROUND(SYS TRUNC(SYS TRUNC(SYS
--------- --------- --------- --------- ---------
15-APR-10 01-APR-10 01-JAN-10 01-APR-10 01-JAN-10 --类型转换
-- to_char
SQL> select empno,ename,hiredate,to_char(hiredate,'fmDD Month YYYY') as hiredate2,
2 to_char(hiredate,'DD MM YYYY') as hiredate3
3 from scott.emp
4 where sal > 2500; EMPNO ENAME HIREDATE HIREDATE2 HIREDATE3
---------- ---------- --------- ----------------- ----------
7566 JONES 02-APR-81 2 April 1981 02 04 1981
7698 BLAKE 01-MAY-81 1 May 1981 01 05 1981
7788 SCOTT 19-APR-87 19 April 1987 19 04 1987
7839 KING 17-NOV-81 17 November 1981 17 11 1981
7902 FORD 03-DEC-81 3 December 1981 03 12 1981 SQL> select to_char(12345.67) as char1,to_char(12345.67,'99,999.99') as char2
2 from dual; CHAR1 CHAR2
-------- ----------
12345.67 12,345.67 --当被转换的数据位数超过格式指定位数,则出现错误。
SQL> select to_char(12345678.90,'99,999.99') as char1 from dual; CHAR1
----------
########## --to_number
SQL> select to_number('970.13') as number1,
2 to_number('970.13') + 35.5 as nunber2,
3 to_number('-$12,345.67','$99,999.99') as number3
4 from dual; NUMBER1 NUNBER2 NUMBER3
---------- ---------- ----------
970.13 1005.63 -12345.67 --to_date
--注意:最终日期采用默认格式DD-MON—YY显示
SQL> select to_date('05-JUL-2008') as date1,to_date('05-JUL-08') as date2,
2 to_date('July 5,2008','MONTH DD,YYYY') as date3,
3 to_date('7.4.08','MM.DD.YY') as date4
4 from dual; DATE1 DATE2 DATE3 DATE4
--------- --------- --------- ---------
05-JUL-08 05-JUL-08 05-JUL-08 04-JUL-08 --case when
SQL> select empno,ename,sal,deptno,case deptno when 20 then 1.10 * sal
2 when 30 then 1.20 * sal
3 else 1.30 * sal end as newsal
4 from scott.emp order by deptno; EMPNO ENAME SAL DEPTNO NEWSAL
---------- ---------- ---------- ---------- ----------
7782 CLARK 2450 10 3185
7839 KING 5000 10 6500
7934 MILLER 1300 10 1690
7566 JONES 2975 20 3272.5
7902 FORD 3000 20 3300
7876 ADAMS 1100 20 1210
7369 SMITH 800 20 880
7788 SCOTT 3000 20 3300
7521 WARD 1250 30 1500
7844 TURNER 1500 30 1800 /*DECODE*/
SQL> select empno,ename,job,sal, decode(job,'CLERK',sal*1.5,'SALESMAN',sal*1.1,sal*1.2) as newsal from scott.emp; EMPNO ENAME JOB SAL NEWSAL
---------- ---------- --------- ---------- ----------
9999 albert
7369 SMITH CLERK 800 1200
7499 ALLEN SALESMAN 1600 1760
7521 WARD SALESMAN 1250 1375
7566 JONES MANAGER 2975 3570
7654 MARTIN SALESMAN 1250 1375
7698 BLAKE MANAGER 2850 3420
7782 CLARK MANAGER 2450 2940
7788 SCOTT ANALYST 3000 3600
7839 KING PRESIDENT 5000 6000
7844 TURNER SALESMAN 1500 1650