原文链接
https://segmentfault.com/q/1010000010352622
希望将下列数组中的sh替换成沪,sz替换成深
var stooges = [
{label:1,value:1,placeCode: 'sh', stock_code: 40},
{label:1,value:1,placeCode: 'sh', stock_code: 50},
{label:1,value:1,placeCode: 'sz', stock_code: 60,status:1},
{label:1,value:1,placeCode: 'sz', stock_code: 39,status:1}
];
我能想到的:
var stooges = [
{label: 1, value: 1, placeCode: 'sh', stock_code: 40},
{label: 1, value: 1, placeCode: 'sh', stock_code: 50},
{label: 1, value: 1, placeCode: 'sz', stock_code: 60, status: 1},
{label: 1, value: 1, placeCode: 'sz', stock_code: 39, status: 1}
]; for (var i = 0; i < stooges.length; i++) {
var item = stooges[i];
if (item.placeCode == "sh") {
item.placeCode = "沪";
}
if (item.placeCode == "sz") {
item.placeCode = "深";
}
}
写个for循环遍历一下,从第一个对象开始,发现对应的placeCode是sh则更新成文字沪,发现对应的placeCode是sz则更新成文字深,一直到最后一个对象
最简便:
for(var i=0;i<stooges.length;i++){
stooges[i].placeCode === 'sh'?stooges[i].placeCode = '沪': stooges[i].placeCode = '深'
}
第二种
var maps= new Map([['sh','沪'],['sz','深圳']]);
stooges = stooges.map(element =>{
element.placeCode = maps.get(element.placeCode);
return element;
});
第三种
var toStr = {
sh : '沪',
sz : '深'
};
stooges.map(function(value){
var placeCode = value.placeCode;
value.placeCode = toStr[placeCode] ? toStr[placeCode] : placeCode;
return value;
});
再次定义一个对象,
定义一个返回vlaue的函数;
map一下