Edit Distance(动态规划,难)

时间:2023-03-09 14:38:54
Edit Distance(动态规划,难)

Given two words word1 and word2, find the minimum number of steps required to convert word1 to word2. (each operation is counted as 1 step.)

You have the following 3 operations permitted on a word:

a) Insert a character
b) Delete a character
c) Replace a character

典型的dp题

class Solution {
public:
int minDistance(string word1, string word2) {
int row=word1.size()+;
int col=word2.size()+;
int isEqual=; int dp[row][col];
for(int i=;i<col;++i){
dp[][i]=i;
}
for(int i=;i<row;++i){
dp[i][]=i;
}
for(int i=;i<row;++i)
for(int j=;j<col;++j){
isEqual=(word1[i-]==word2[j-])?:;
dp[i][j]=min(dp[i-][j]+,min(dp[i][j-]+,dp[i-][j-]+isEqual));
}
return dp[row-][col-];
}
};