i = ["iphone 6000", "bicycle 1000", "coffee 50", "python book 100", "italy pizza 200", ]
j = ["] # 运用列表嵌套更容易实现
in_list = [] # 已购买物品列表
salary = int(input("你的工资："))
while salary > 0: # 循环的开始以工资余额大于零开始
# a = 0 # 循环打印利于管理员账户的管理
# while a < 5:
# print("{xuhao}" .format(xuhao=a+1), i[a]) # 生硬的加个序号 下面注释的是更简单的方法
# a += 1
for d, e in enumerate(i, 1):
print(d, ">>>", e)
w_i = input("你想要的物品序号或者退出q")
if w_i.isdigit(): # 判断是否数字（输入的都是字符串）
w_i = int(w_i)
if 0 < w_i <= len(i): # len 计算长度
if salary > int(j[w_i-1]):
salary -= int(j[w_i-1]) # 余额变成工资 接着循环
in_list.append(i[w_i-1]) # 加入购物车列表
print(i[w_i-1], "已加入你的购物车")
else:
print("您的余额不足")
elif w_i == "q":
break
elif w_i == "manager":
print("0:增加商品 1：下架商品 2：修改价格 ")
keyword = int(input("输入命令序号："))
if keyword == 0:
name_staff = str(input("输入商品名"))
ordor_staff = int(input("输入商品序号"))
price_staff = input("输入价格")
name_staff = " ".join([name_staff,price_staff])
j.insert(ordor_staff-1, price_staff)
i.insert(ordor_staff-1, name_staff)
elif keyword == 1:
ordor_staff = int(input("输入商品序号"))
l = i.pop(ordor_staff - 1)
print("已删除：", l)
elif keyword == 2:
ordor_staff = int(input("修改的序号"))
gai_price = input("修改的价格")
j[ordor_staff-1] = gai_price
f = i[ordor_staff-1] # iho 6000
u = j[ordor_staff - 1] # u =1
v = "".join([f,"降价为"])
i[ordor_staff-1] = " ".join([v,u])
else:
print("眼瞎呀")
else:
print("非法字符")
print("您已经购买：")
for b in in_list:
print(b)
print("您的余额为：", salary)
简易购物车系统