sf02_选择排序算法Java Python rust 实现

时间:2023-03-10 06:41:33
sf02_选择排序算法Java Python rust 实现

Java 实现

package common;

public class SimpleArithmetic {

    /**
* 选择排序
* 输入整形数组:a[n] 【4、5、3、7】
* 1. 取数组编号为i(i属于[0 , n-2])的数组值 a[i],即第一重循环
* 2. 假定a[i]为数组a[k](k属于[i,n-1])中的最小值a[min],即执行初始化 min =i
* 3. 取数组编号为m(m属于[i+1,n-1])的数组值 a[m],即第二重循环
* 4. 若 a[m] < a[min], 则 min = m ; min 始终记录 a[k]中的最小值
* 5. 当 min != i时,即第二步的假定a[i]为a[k]中的最小值不成立时,需要将a[min]与a[i]的值互换
*
* @param arr 整形数组
*/
public static void selectSort(int[] arr){
int n = arr.length;
int min = 0;
int tmp = 0;
for(int i = 0; i < n-1; i++){
min = i;
for(int m = i + 1; m < n; m++){
if(arr[m]<arr[min]) min =m;
}
if(i != min){
tmp = arr[i];
arr[i] = arr[min];
arr[min] = tmp;
}//end of if
}//end of for } public static void main(String[] args) {
// TODO 自动生成的方法存根
int[] arr = {12,23,9,24,15,3,18};
SimpleArithmetic.selectSort(arr); for(int i = 0; i < arr.length; i++){
System.out.print(arr[i]+" ");
}
//输出 3 9 12 15 18 23 24 } }

Python 实现

Python 2.7.9 (default, Dec 10 2014, 12:24:55) [MSC v.1500 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> class SimpleArithmetic:
def selectSort(self,arr):
v_len = len(arr)
v_index_i = 0
while v_index_i != v_len -1:
i = arr[v_index_i]
v_min = i
for m in arr[v_index_i+1:v_len]:
if m < v_min:
v_min = m
if i != v_min:
v_tmp = arr.index(v_min)
arr[v_index_i] = v_min
arr[v_tmp] = i
v_index_i = v_index_i + 1 >>> sa = SimpleArithmetic()
>>> arr = [12,23,9,24,15,3,18]
>>> sa.selectSort(arr)
>>> arr
[3, 9, 12, 15, 18, 23, 24]
>>>

rust实现

pub fn select_sort_vec(v1: &mut Vec<i32>){
let le = v1.len(); let mut tmp_min_index = 0; for i in 0..(le-1) {
if let Some(elem) = v1.get(i){
tmp_min_index = i; for m in (i+1)..le {
if let Some(e) = v1.get(m) {
if let Some(emin) = v1.get(tmp_min_index){
if *e < *emin{
tmp_min_index = m;
}
};
}
} if i != tmp_min_index {
v1.swap(i,tmp_min_index);
}
}
}
} pub fn select_sort_vec_test() {
let mut v1 = vec![1, 3, 2,5,11,4,9];
select_sort_vec(&mut v1); for (i,val) in v1.iter().enumerate() {
println!("last {}:{}",i,val);
}
}