C语言 · 报时助手

基础练习 报时助手  

时间限制：1.0s   内存限制：512.0MB

锦囊1

　　判断，字符串输出。

锦囊2

　　按要求输出，判断特殊情况。

问题描述

　　给定当前的时间，请用英文的读法将它读出来。
　　时间用时h和分m表示，在英文的读法中，读一个时间的方法是：
　　如果m为0，则将时读出来，然后加上“o'clock”，如3:00读作“three o'clock”。
　　如果m不为0，则将时读出来，然后将分读出来，如5:30读作“five thirty”。
　　时和分的读法使用的是英文数字的读法，其中0~20读作：
　　0:zero, 1: one, 2:two, 3:three, 4:four, 5:five, 6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven, 12:twelve, 13:thirteen, 14:fourteen, 15:fifteen, 16:sixteen, 17:seventeen, 18:eighteen, 19:nineteen, 20:twenty。
　　30读作thirty，40读作forty，50读作fifty。
　　对于大于20小于60的数字，首先读整十的数，然后再加上个位数。如31首先读30再加1的读法，读作“thirty one”。
　　按上面的规则21:54读作“twenty one fifty four”，9:07读作“nine seven”，0:15读作“zero fifteen”。

输入格式

　　输入包含两个非负整数h和m，表示时间的时和分。非零的数字前没有前导0。h小于24，m小于60。

输出格式

　　输出时间时刻的英文。

样例输入

0 15

样例输出

zero fifteen

代码一：

 /*
 0:zero, 1: one, 2:two, 3:three, 4:four, 5:five
 6:six, 7:seven, 8:eight, 9:nine, 10:ten, 11:eleven
 12:twelve, 13:thirteen, 14:fourteen, 15:fifteen
 16:sixteen, 17:seventeen, 18:eighteen, 19:nineteen
 20:twenty, 30:thirty，40:forty，50:fifty。

 对于大于20小于60的数字，首先读整十的数，然后再加上个位数。
     如31首先读30再加1的读法，读作“thirty one”。
 按上面的规则:
     21:54读作“twenty one fifty four”;
     9:07读作“nine seven”;
     0:15读作“zero fifteen”。
 */
 #include<stdio.h>
 int main(){
     char a[][]={"zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen","twenty"};
     char b[][]={"","","twenty","thirty","forty","fifty"};
     int h,m;
     scanf("%d%d",&h,&m);
     if(m==){
         if(h<=)
             printf("%s o'clock",a[h]);
         else
             printf("%s %s",b[h/],a[h%]);
     }else{
         if(h<=){
             if(m<=){
                 printf("%s %s",a[h],a[m]);
             }else{
                 printf("%s %s %s",a[h],b[m/],a[m%]);
             }
         }else{
             if(m<=){
                 printf("%s %s %s",b[h/],a[h%],a[m]);
             }else{
                 printf("%s %s %s %s",b[h/],a[h%],b[m/],a[m%]);
             }
         }
     }
     return ;
 }

代码二：

 #include<stdio.h>
 void ass(int number){
     char n[][]={"zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen","twenty",
     "thirty","forty","fifty"};
     int a=number/;
     int b=number%;
     if(number<=){
         printf("%s",n[number]);
     }else{
         if(b!=){
             printf(" %s",n[b]);
         }
         printf("%s",n[number+]);
     }
 }
 void time_ass(int hour,int minu){
     if(minu==){//整点
         ass(hour);
         printf(" o'clock");
     }else{//非整点
         ass(hour);
         printf(" ");
         ass(minu);
     }
 }
 int main(){
     int h,m;
     scanf("%d%d",&h,&m);
     time_ass(h,m);
     return ;
 }