hdu 3549 Flow Problem 最大流 Dinic

时间:2023-03-09 18:58:20
hdu 3549 Flow Problem 最大流 Dinic

题目链接

题意

裸的最大流。

学习参考

http://www.cnblogs.com/SYCstudio/p/7260613.html

Code

#include <bits/stdc++.h>
#define inf 0x3f3f3f3f
#define maxm 1010
#define maxn 20
using namespace std;
typedef long long LL;
struct Edge {
int to, ne, c;
}edge[maxm<<1];
int tot, ne[maxn], dep[maxn];
void add(int u, int v, int c) {
edge[tot] = {v, ne[u], c};
ne[u] = tot++;
}
int n, m, u, v, c;
int bfs(int src) {
queue<int> q;
while (!q.empty()) q.pop();
memset(dep, 0, sizeof(dep));
dep[src] = 1;
q.push(src);
while (!q.empty()) {
int u = q.front(); q.pop();
for (int i = ne[u]; ~i; i = edge[i].ne) {
int v = edge[i].to;
if (edge[i].c > 0 && !dep[v]) {
dep[v] = dep[u]+1;
q.push(v);
}
}
}
return dep[n];
}
int dfs(int u, int flow) {
if (u == n) return flow;
int ret = 0;
for (int i = ne[u]; ~i; i = edge[i].ne) {
int v = edge[i].to;
if (edge[i].c > 0 && dep[v]-dep[u]==1) {
int c = dfs(v, min(flow-ret, edge[i].c));
edge[i].c -= c;
edge[i^1].c += c;
ret += c;
if (ret == flow) break;
}
}
if (!flow) dep[u] = 0;
return ret;
}
int kas;
void work() {
scanf("%d%d", &n, &m);
tot = 0; memset(ne, -1, sizeof(ne));
for (int i = 0; i < m; ++i) {
scanf("%d%d%d", &u, &v, &c);
add(u, v, c);
add(v, u, 0);
}
int ans = 0, ret;
while (bfs(1)) {
while (ret = dfs(1, inf)) ans += ret;
}
printf("Case %d: %d\n", ++kas, ans);
}
int main() {
// freopen("in.txt", "r", stdin);
int T;
scanf("%d", &T);
while (T--) work();
return 0;
}