Codeforces Round #274 (Div. 2) --A Expression

主题链接：Expression

Expression

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Petya studies in a school and he adores Maths. His class has been studying arithmetic expressions. On the last class the teacher wrote three positive integers a, b, c on
the blackboard. The task was to insert signs of operations '+' and '*',
and probably brackets between the numbers so that the value of the resulting expression is as large as possible. Let's consider an example: assume that the teacher wrote numbers 1, 2 and 3 on the blackboard. Here are some ways of placing signs and brackets:

1+2*3=7
1*(2+3)=5
1*2*3=6
(1+2)*3=9

Note that you can insert operation signs only between a and b,
and between b and c, that is, you cannot swap integers.
For instance, in the given sample you cannot get expression (1+3)*2.

It's easy to see that the maximum value that you can obtain is 9.

Your task is: given a, b and c print
the maximum value that you can get.

Input

The input contains three integers a, b and c,
each on a single line (1 ≤ a, b, c ≤ 10).

Output

Print the maximum value of the expression that you can obtain.

Sample test(s)

input

output

input

output

大致题意：a, b, c三个数。在三个数中，插入“+” 和“*”运算符的随意两个组合，求能组成的表达式的值得最大值。（能够用括号）

解题思路：没啥说的。直接暴力，总共就6种组合。

AC代码：

#include <stdio.h>

#include <string.h>

#include <iostream>

#include <algorithm>

#include <vector>

#include <queue>

#include <set>

#include <map>

#include <string>

#include <math.h>

#include <stdlib.h>

#include <time.h>

using namespace std;

#define INF 0x7fffffff

int x[9];

int main()

{

//    #ifdef sxk

//        freopen("in.txt","r",stdin);

//    #endif

    int a,b,c;

    while(scanf("%d%d%d",&a,&b,&c)!=EOF)

    {

        x[0] = a + b + c;

        x[1] = a + (b * c);

        x[2] = a * (b + c);

        x[3] = (a + b) * c;

        x[4] = (a * b) + c;

        x[5] = a * b * c;

        sort(x, x+6);

        printf("%d\n",x[5]);

    }

    return 0;

}

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Codeforces Round #274 (Div. 2) --A Expression

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