poj 3304(直线与线段相交)

时间:2023-03-09 05:11:00
poj 3304(直线与线段相交)

传送门:Segments

题意:线段在一个直线上的摄影相交 求求是否存在一条直线,使所有线段到这条直线的投影至少有一个交点

分析:可以在共同投影处作原直线的垂线,则该垂线与所有线段都相交<==> 是否存在一条直线与所有线段都相交。 去盗了一份bin神的模板,用起来太方便了。。。

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <algorithm>
#include <queue>
#include <map>
#include <vector>
#include <set>
#include <string>
#include <math.h> using namespace std; const double eps = 1e-;
const double PI = acos(-1.0);
const int N = ;
int sgn(double x)
{
if(fabs(x) < eps)return ;
if(x < )return -;
else return ;
}
struct Point
{
double x,y;
Point(){}
Point(double _x,double _y)
{
x = _x;y = _y;
}
Point operator -(const Point &b)const
{
return Point(x - b.x,y - b.y);
}
//叉积
double operator ^(const Point &b)const
{
return x*b.y - y*b.x;
}
//点积
double operator *(const Point &b)const
{
return x*b.x + y*b.y;
}
//绕原点旋转角度B(弧度值),后x,y的变化
void transXY(double B)
{
double tx = x,ty = y;
x = tx*cos(B) - ty*sin(B);
y = tx*sin(B) + ty*cos(B);
}
//绕点p逆时针旋转角度B(弧度值)
void rotate(Point p,double B)
{
Point v=(*this)-p;
double tx = v.x,ty = v.y;
x = tx*cos(B) - ty*sin(B);
y = tx*sin(B) + ty*cos(B);
}
};
struct Line
{
Point s,e;
Line(){}
Line(Point _s,Point _e)
{
s = _s;e = _e;
}
//两直线相交求交点
//第一个值为0表示直线重合,为1表示平行,为0表示相交,为2是相交
//只有第一个值为2时,交点才有意义
pair<int,Point> operator &(const Line &b)const
{
Point res = s;
if(sgn((s-e)^(b.s-b.e)) == )
{
if(sgn((s-b.e)^(b.s-b.e)) == )
return make_pair(,res);//重合
else return make_pair(,res);//平行
}
double t = ((s-b.s)^(b.s-b.e))/((s-e)^(b.s-b.e));
res.x += (e.x-s.x)*t;
res.y += (e.y-s.y)*t;
return make_pair(,res);
}
};
//*两点间距离
double dist(Point a,Point b)
{
return sqrt((a-b)*(a-b));
}
//*判断线段相交
bool inter(Line l1,Line l2)
{
return
max(l1.s.x,l1.e.x) >= min(l2.s.x,l2.e.x) &&
max(l2.s.x,l2.e.x) >= min(l1.s.x,l1.e.x) &&
max(l1.s.y,l1.e.y) >= min(l2.s.y,l2.e.y) &&
max(l2.s.y,l2.e.y) >= min(l1.s.y,l1.e.y) &&
sgn((l2.s-l1.e)^(l1.s-l1.e))*sgn((l2.e-l1.e)^(l1.s-l1.e)) <= &&
sgn((l1.s-l2.e)^(l2.s-l2.e))*sgn((l1.e-l2.e)^(l2.s-l2.e)) <= ;
}
//判断直线和线段相交
bool Seg_inter_line(Line l1,Line l2) //判断直线l1和线段l2是否相交
{
return sgn((l2.s-l1.e)^(l1.s-l1.e))*sgn((l2.e-l1.e)^(l1.s-l1.e)) <= ;
}
//点到直线距离
//返回为result,是点到直线最近的点
Point PointToLine(Point P,Line L)
{
Point result;
double t = ((P-L.s)*(L.e-L.s))/((L.e-L.s)*(L.e-L.s));
result.x = L.s.x + (L.e.x-L.s.x)*t;
result.y = L.s.y + (L.e.y-L.s.y)*t;
return result;
}
//点到线段的距离
//返回点到线段最近的点
Point NearestPointToLineSeg(Point P,Line L)
{
Point result;
double t = ((P-L.s)*(L.e-L.s))/((L.e-L.s)*(L.e-L.s));
if(t >= && t <= )
{
result.x = L.s.x + (L.e.x - L.s.x)*t;
result.y = L.s.y + (L.e.y - L.s.y)*t;
}
else
{
if(dist(P,L.s) < dist(P,L.e))
result = L.s;
else result = L.e;
}
return result;
}
//计算多边形面积
//点的编号从0~n-1
double CalcArea(Point p[],int n)
{
double res = ;
for(int i = ;i < n;i++)
res += (p[i]^p[(i+)%n])/;
return fabs(res);
}
//*判断点在线段上
bool OnSeg(Point P,Line L)
{
return
sgn((L.s-P)^(L.e-P)) == &&
sgn((P.x - L.s.x) * (P.x - L.e.x)) <= &&
sgn((P.y - L.s.y) * (P.y - L.e.y)) <= ;
}
//*判断点在凸多边形内
//点形成一个凸包,而且按逆时针排序(如果是顺时针把里面的<0改为>0)
//点的编号:0~n-1
//返回值:
//-1:点在凸多边形外
//0:点在凸多边形边界上
//1:点在凸多边形内
int inConvexPoly(Point a,Point p[],int n)
{
for(int i = ;i < n;i++)
{
if(sgn((p[i]-a)^(p[(i+)%n]-a)) < )return -;
else if(OnSeg(a,Line(p[i],p[(i+)%n])))return ;
}
return ;
}
//*判断点在任意多边形内
//射线法,poly[]的顶点数要大于等于3,点的编号0~n-1
//返回值
//-1:点在凸多边形外
//0:点在凸多边形边界上
//1:点在凸多边形内
int inPoly(Point p,Point poly[],int n)
{
int cnt;
Line ray,side;
cnt = ;
ray.s = p;
ray.e.y = p.y;
ray.e.x = -100000000000.0;//-INF,注意取值防止越界 for(int i = ;i < n;i++)
{
side.s = poly[i];
side.e = poly[(i+)%n]; if(OnSeg(p,side))return ; //如果平行轴则不考虑
if(sgn(side.s.y - side.e.y) == )
continue; if(OnSeg(side.s,ray))
{
if(sgn(side.s.y - side.e.y) > )cnt++;
}
else if(OnSeg(side.e,ray))
{
if(sgn(side.e.y - side.s.y) > )cnt++;
}
else if(inter(ray,side))
cnt++;
}
if(cnt % == )return ;
else return -;
}
//判断凸多边形
//允许共线边
//点可以是顺时针给出也可以是逆时针给出
//点的编号1~n-1
bool isconvex(Point poly[],int n)
{
bool s[];
memset(s,false,sizeof(s));
for(int i = ;i < n;i++)
{
s[sgn( (poly[(i+)%n]-poly[i])^(poly[(i+)%n]-poly[i]) )+] = true;
if(s[] && s[])return false;
}
return true;
}
Line seg[N];
int n;
bool judge(Point a,Point b)
{
if(sgn(dist(a,b))==)return false;
Line l=Line(a,b);
for(int i=;i<=n;i++)
if(!Seg_inter_line(l,seg[i]))return false;
return true;
}
int main()
{
int T;
scanf("%d",&T);
while(T--)
{
scanf("%d",&n);
for(int i=;i<=n;i++)
{
double a,b,c,d;
scanf("%lf%lf%lf%lf",&a,&b,&c,&d);
seg[i]=Line(Point(a,b),Point(c,d));
}
bool flag=false;
for(int i=;i<=n&&!flag;i++)
{
for(int j=;j<=n;j++)
if(judge(seg[i].s,seg[j].s)||judge(seg[i].s,seg[j].e)||
judge(seg[i].e,seg[j].s)||judge(seg[i].e,seg[j].e))
{
flag=true;break;
}
}
if(flag)puts("Yes!");
else puts("No!");
}
return ;
}