Java8 Stream()关于在所有用户的所有上传记录中,找出每个用户最新上传记录

时间:2023-03-09 18:41:31
Java8 Stream()关于在所有用户的所有上传记录中,找出每个用户最新上传记录

原创文章:转载请标明出处 https://www.cnblogs.com/yunqing/p/9504196.html

首先分析相当于如下,在所有的猫中,每个名字的猫都保留年龄最小的一个

import java.util.ArrayList;
import java.util.Comparator;
import java.util.LinkedList;
import java.util.List;
import java.util.Map;
import java.util.Set;
import java.util.stream.Collectors; public class test { public static void main(String[] args) {
List<Cat> list = new ArrayList<>();
list.add(new Cat("小花",1,1));
list.add(new Cat("小花",2,1));
list.add(new Cat("小2",3,1));
list.add(new Cat("小2",4,1));
list.add(new Cat("小3",5,1));
list.add(new Cat("小3",7,1));
list.add(new Cat("小花",3,1));
list.add(new Cat("小1",1,1));
list.add(new Cat("小1",2,1));
list.add(new Cat("小1",3,1));
list.add(new Cat("小3",3,1));
list.add(new Cat("小3",12,1)); List<Cat> result = new LinkedList<>(); Map<String, List<Cat>> res = list.stream().collect(Collectors.groupingBy(Cat::getName));
Set<String> keys = res.keySet(); for (String str : keys) {
List<Cat> groupList = list.stream().filter(e->e.getName().equals(str)).collect(Collectors.toList());
//以下两行都是找出组内年龄最小的猫
//Cat catMinAge0 = groupList.stream().reduce((one, two) -> one.getAge() < two.getAge() ? one : two).orElse(null);
Cat catMinAge1 = groupList.stream().min(Comparator.comparingInt(o -> o.getAge())).orElse(null);
result.add(catMinAge1);
} System.out.println(result); } } class Cat{
private String name;
private int age;
private int gender;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public int getGender() {
return gender;
}
public void setGender(int gender) {
this.gender = gender;
}
public Cat() {}
public Cat(String name, int age, int gender) {
super();
this.name = name;
this.age = age;
this.gender = gender;
}
@Override
public String toString() {
return "Cat [name=" + name + ", age=" + age + ", gender=" + gender + "]";
} }

  测试完毕,拿到项目中使用如下:

	@Override
@Transactional
public List<DrivingRecord> findByCityCodeAndRecordTimeStartingWith(String cityCode, String recondTime) {
//查询此区域今天所有用户的所有上报记录
List<DrivingRecord> list = drivingRecondDao.findByCityCodeAndRecordTimeStartingWith(cityCode, recondTime);
List<DrivingRecord> resultList = new ArrayList<>();
//先根据用户分组,把同一个用户的上报记录放到同一个组
Map<User, List<DrivingRecord>> map = list.stream()
.collect(Collectors.groupingBy(DrivingRecord::getUser));
//取出所有用户key值
Set<User> keys = map.keySet();
//遍历所有用户
for (User user : keys) {
//找出与当前用户的分组
List<DrivingRecord> groupList = list.stream()
.filter(u->u.getUser().equals(user))
.collect(Collectors.toList());
//比较时间,取当前用户的最新上报的记录
DrivingRecord dr = groupList.stream()
.reduce((one,two)->one.getRecordTime().isBefore(two.getRecordTime())?two:one)
.orElse(null);
//把所有用户的最新上报信息填到resultList
resultList.add(dr);
} return resultList;
}