python 中zip函数的使用时间:2023-03-09 15:37:57 1.ta = [1,2,3] tb = [9,8,7] tc = ['a','b','c'] for (a,b,c) in zip(ta,tb,tc): print(a,b,c) 2. ta = [1,2,3]tb = [9,8,7] # clusterzipped = zip(ta,tb)print(zipped) # decomposena, nb = zip(*zipped)print(na, nb)