Palindrome Numbers UVA - 12050(第几个回文数)

时间:2024-05-01 17:39:39

Palindrome Numbers UVA - 12050(第几个回文数)Palindrome Numbers UVA - 12050(第几个回文数)

长度为k的回文串个数有9*10^(k-1)
#include <iostream>
#include <cstdio>
#include <sstream>
#include <cstring>
#include <map>
#include <set>
#include <vector>
#include <stack>
#include <queue>
#include <algorithm>
#include <cmath>
#define MOD 2018
#define LL long long
#define ULL unsigned long long
#define Pair pair<int, int>
#define mem(a, b) memset(a, b, sizeof(a))
#define _ ios_base::sync_with_stdio(0),cin.tie(0)
//freopen("1.txt", "r", stdin);
using namespace std;
const int maxn = , INF = 0x7fffffff;
int num[maxn], a[maxn];
void init()
{
num[] = num[] = ;
for(int i=; i<; i+=)
num[i] = num[i+] = num[i-] * ;
} int main()
{
init();
LL n;
while(cin>> n && n)
{
mem(a, );
int len = ;
while(n - num[len] > )
{
n -= num[len];
len++;
}
n--;
for(int i=len/+; i<=len; i++)
{
a[i] = n%;
n /= ;
}
a[len]++;
for(int i=; i<=len/; i++)
a[i] = a[len-i+];
for(int i=; i<=len; i++)
printf("%d", a[i]);
printf("\n"); }
return ;
}