[C/CPP系列知识] 那些程序C语言可以编译通过但C++无法编译成功 Write a C program that won’t compile in C++

时间:2023-03-08 23:56:24
[C/CPP系列知识] 那些程序C语言可以编译通过但C++无法编译成功   Write a C program that won’t compile in C++

http://www.geeksforgeeks.org/write-c-program-wont-compiler-c/

1) C++中在函数声明之前调用一个函数会引发错误,但是在C中有可能可以。 参考 http://www.cnblogs.com/diegodu/p/4580292.html

下面的程序可以用gcc编译,但g++无法编译。

#include<stdio.h>
int main()
{
foo(); // foo() is called before its declaration/definition
} int foo()
{
printf("Hello");
return ;
}

编译结果:

diego@ubuntu:~/myProg/geeks4geeks/cpp$ gcc test3.c
diego@ubuntu:~/myProg/geeks4geeks/cpp$ g++ test3.c
test3.c: In function 'int main()':
test3.c::: error: 'foo' was not declared in this scope
foo(); // foo() is called before its declaration/definition

2) C++中将一个非const指针指向一个const变量是非法的,但在C中是可以的。

#include <stdio.h>

int main(void)
{
int const j = ; /* The below assignment is invalid in C++, results in error
In C, the compiler *may* throw a warning, but casting is
implicitly allowed */
int *ptr = &j; // A normal pointer points to const printf("*ptr: %d\n", *ptr); return ;
}

编译结果:

diego@ubuntu:~/myProg/geeks4geeks/cpp$ gcc test4.c
test4.c: In function 'main':
test4.c::: warning: initialization discards 'const' qualifier from pointer target type [enabled by default]
int *ptr = &j; // A normal pointer points to const
^
diego@ubuntu:~/myProg/geeks4geeks/cpp$ g++ test4.c
test4.c: In function 'int main()':
test4.c::: error: invalid conversion from 'const int*' to 'int*' [-fpermissive]
int *ptr = &j; // A normal pointer points to const
   ^

3) C中可以将void* 赋值给其他的指针,如int*, char*等,但是在C++中则需要显示的类型转换。

#include <stdio.h>
int main()
{
void *vptr;
int *iptr = vptr; //In C++, it must be replaced with int *iptr=(int *)vptr;
return ;
}

编译结果:

diego@ubuntu:~/myProg/geeks4geeks/cpp$ gcc test5.c
diego@ubuntu:~/myProg/geeks4geeks/cpp$ g++ test5.c
test5.c: In function 'int main()':
test5.c::: error: invalid conversion from 'void*' to 'int*' [-fpermissive]
int *iptr = vptr; //In C++, it must be replaced with int *iptr=(int *)vptr;

这也就意味着在C++中我们调用malloc时需要显示的转换类型,“int *p = (void *)malloc(sizeof(int)),而在C中不需要。

4) C++中const变量声明的同时必须赋初值,但C中不需要赋初值。

#include <stdio.h>
int main()
{
const int a; // LINE 4
return ;
}

编译结果:

diego@ubuntu:~/myProg/geeks4geeks/cpp$ gcc test6.c
diego@ubuntu:~/myProg/geeks4geeks/cpp$ g++ test6.c
test6.c: In function 'int main()':
test6.c::: error: uninitialized const 'a' [-fpermissive]
const int a; // LINE 4
^

5) C++中的关键字在C中不可用,如new,delete,explicit等。

#include <stdio.h>
int main(void)
{
int new = ; // new is a keyword in C++, but not in C
printf("%d", new);
}

6) C++有着更加严格的类型检查。C++无法通过编译,有error,C中仅仅报warning

#include <stdio.h>
int main()
{
char *c = ;
printf("c = %u", c);
return ;
}

编译结果:

diego@ubuntu:~/myProg/geeks4geeks/cpp$ gcc test7.c
test7.c: In function 'main':
test7.c::: warning: initialization makes pointer from integer without a cast [enabled by default]
char *c = ;
^
test7.c::: warning: format '%u' expects argument of type 'unsigned int', but argument has type 'char *' [-Wformat=]
printf("c = %u", c);
^
diego@ubuntu:~/myProg/geeks4geeks/cpp$ g++ test7.c
test7.c: In function 'int main()':
test7.c::: error: invalid conversion from 'int' to 'char*' [-fpermissive]
char *c = ;
^
test7.c::: warning: format '%u' expects argument of type 'unsigned int', but argument has type 'char*' [-Wformat=]
printf("c = %u", c);
^

7) C++变量可以在任意位置定义,但是C中必须是一个语句块开始的地方。(gcc 中可以编译。。)

#include <stdio.h>
int main()
{
int i;
i=;
i++;
int j;
return ;
}

8) C++存在loop variable,C中不存在。

#include <stdio.h>
int main()
{
for(int i=; i<; i++)
; return ;
}

9) C++ main函数必须返回int,C可以返回void

#include <stdio.h>
void main (int argc, char *argv[])
{
printf("bye\n");
}

编译结果:

diego@ubuntu:~/myProg/geeks4geeks/cpp$ gcc test9.c
diego@ubuntu:~/myProg/geeks4geeks/cpp$ g++ test9.c
test9.c::: error: '::main' must return 'int'
void main (int argc, char *argv[])
^
diego@ubuntu:~/myProg/geeks4geeks/cpp$