从一个表中选择多个行

时间:2022-09-21 16:00:27

This is my table structure

这是我的表格结构。

id name value
1 questions 50
2 duration 120

id名值1问题50 2持续120

Now, i want to display the value according to the name. I am unable to do the sql statement correct. This is what i have done:

现在,我要根据名称显示值。我无法正确地执行sql语句。这就是我所做的:

$qry = "SELECT * FROM (
SELECT (SELECT value FROM pq_examsettings) as duration,
       (SELECT value FROM pq_examsettings) as questions
 ) ";
$result= mysql_query($qry);
$row = mysql_fetch_array($result);
$duration = $row['duration'];
$questions = $row['questions'];

Somebody help me on how i can do my query such that my $duration and $questions variables display 120 and 50.

有人可以帮助我如何进行查询,使$duration和$questions变量显示120和50。

3 个解决方案

#1


4  

give this a try,

给这一个尝试,

SELECT  MAX(CASE WHEN name = 'questions' THEN value END) questions,
        MAX(CASE WHEN name = 'duration' THEN value END) duration 
FROM    pq_examsettings

#2


0  

I'm not familiar enough with MySQL to know a simple way to transpose rows to columns and return the results in one select-- looks like JW gave an answer that does that.

我对MySQL还不够熟悉,不知道如何将行转换为列并在一个选择中返回结果——看起来JW给出了这样的答案。

Another option would be to just make two database calls:

另一种选择是只进行两次数据库调用:

$qry = "SELECT value FROM PQ_EXAMSETTINGS WHERE NAME = 'duration'";
$result= mysql_query($qry);
$row = mysql_fetch_array($result);
$duration = $row['value'];

$qry = "SELECT value FROM PQ_EXAMSETTINGS WHERE NAME = 'questions'";
$result= mysql_query($qry);
$row = mysql_fetch_array($result);
$questions = $row['value'];

#3


0  

Use mysqli or pdo functions the mysql_* functions are officially deprecated:

使用mysqli或pdo函数,mysql_*函数被正式弃用:

$mysqli = new mysqli($dbserver, $dbmanager, $dbpass, $dbname);
if($mysqli->connect_errno) {
    echo "Error connecting to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}

$query = $mysqli->query("SELECT * FROM pq_examsettings");
if($query->num_rows){
$new_row = array();
while($row = $query->fetch_assoc()){
    foreach($row as $key => $value){
        if($key == 'name'){
            $array_key = $value;
        }
        if($key == 'value'){
            $new_row[$array_key] = $value;
        }
    }
}
$duration = $new_row['duration'];
$questions = $new_row['questions'];
}

#1


4  

give this a try,

给这一个尝试,

SELECT  MAX(CASE WHEN name = 'questions' THEN value END) questions,
        MAX(CASE WHEN name = 'duration' THEN value END) duration 
FROM    pq_examsettings

#2


0  

I'm not familiar enough with MySQL to know a simple way to transpose rows to columns and return the results in one select-- looks like JW gave an answer that does that.

我对MySQL还不够熟悉,不知道如何将行转换为列并在一个选择中返回结果——看起来JW给出了这样的答案。

Another option would be to just make two database calls:

另一种选择是只进行两次数据库调用:

$qry = "SELECT value FROM PQ_EXAMSETTINGS WHERE NAME = 'duration'";
$result= mysql_query($qry);
$row = mysql_fetch_array($result);
$duration = $row['value'];

$qry = "SELECT value FROM PQ_EXAMSETTINGS WHERE NAME = 'questions'";
$result= mysql_query($qry);
$row = mysql_fetch_array($result);
$questions = $row['value'];

#3


0  

Use mysqli or pdo functions the mysql_* functions are officially deprecated:

使用mysqli或pdo函数,mysql_*函数被正式弃用:

$mysqli = new mysqli($dbserver, $dbmanager, $dbpass, $dbname);
if($mysqli->connect_errno) {
    echo "Error connecting to MySQL: (" . $mysqli->connect_errno . ") " . $mysqli->connect_error;
}

$query = $mysqli->query("SELECT * FROM pq_examsettings");
if($query->num_rows){
$new_row = array();
while($row = $query->fetch_assoc()){
    foreach($row as $key => $value){
        if($key == 'name'){
            $array_key = $value;
        }
        if($key == 'value'){
            $new_row[$array_key] = $value;
        }
    }
}
$duration = $new_row['duration'];
$questions = $new_row['questions'];
}