In my activity, I create a Bitmap
object and then I need to launch another Activity
, How can I pass this Bitmap
object from the sub-activity (the one which is going to be launched)?
在我的活动中,我创建一个位图对象,然后我需要启动另一个活动,如何从子活动(即将启动的活动)传递这个位图对象?
8 个解决方案
#1
261
Bitmap
implements Parcelable
, so you could always pass it with the intent:
位图实现了可分割性,所以您总是可以传递它的意图:
Intent intent = new Intent(this, NewActivity.class);
intent.putExtra("BitmapImage", bitmap);
and retrieve it on the other end:
并在另一端检索:
Intent intent = getIntent();
Bitmap bitmap = (Bitmap) intent.getParcelableExtra("BitmapImage");
#2
19
Actually, passing a bitmap as a Parcelable will result in a "JAVA BINDER FAILURE" error. Try passing the bitmap as a byte array and building it for display in the next activity.
实际上,将位图作为可分配的传递将导致“JAVA绑定失败”错误。尝试将位图作为字节数组传递,并构建它以便在下一个活动中显示。
I shared my solution here:
how do you pass images (bitmaps) between android activities using bundles?
我在这里分享了我的解决方案:如何使用bundle在android活动之间传递图像(位图)?
#3
8
Passsing bitmap as parceable in bundle between activity is not a good idea because of size limitation of Parceable(1mb). You can store the bitmap in a file in internal storage and retrieve the stored bitmap in several activities. Here's some sample code.
由于parceable (1mb)的大小限制,在活动之间将位图作为分组进行分组传递不是一个好主意。您可以在内部存储的文件中存储位图,并在多个活动中检索存储的位图。这里有一些示例代码。
To store bitmap in a file myImage in internal storage:
将位图存储在内部存储的myfile映像中:
public String createImageFromBitmap(Bitmap bitmap) {
String fileName = "myImage";//no .png or .jpg needed
try {
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
FileOutputStream fo = openFileOutput(fileName, Context.MODE_PRIVATE);
fo.write(bytes.toByteArray());
// remember close file output
fo.close();
} catch (Exception e) {
e.printStackTrace();
fileName = null;
}
return fileName;
}
Then in the next activity you can decode this file myImage to a bitmap using following code:
然后在下一个活动中,您可以使用以下代码将这个文件myImage解码到位图:
Bitmap bitmap = BitmapFactory.decodeStream(context
.openFileInput("myImage"));//here context can be anything like getActivity() for fragment, this or MainActivity.this
Note A lot of checking for null and scaling bitmap's is ommited.
注意,很多对null和缩放位图的检查都被省略了。
#4
4
If the image is too large and you can't save&load it to the storage, you should consider just using a global static reference to the bitmap (inside the receiving activity), which will be reset to null on onDestory, only if "isChangingConfigurations" returns true.
如果图像太大,无法保存并加载到存储中,您应该考虑使用位图的全局静态引用(在接收活动中),只有当“isChangingConfigurations”返回true时,该位图将在onDestory上重置为null。
#5
3
Because Intent has size limit . I use public static object to do pass bitmap from service to broadcast ....
因为意图有大小限制。我使用公共静态对象通过位图从服务广播....
public class ImageBox {
public static Queue<Bitmap> mQ = new LinkedBlockingQueue<Bitmap>();
}
pass in my service
通过我的服务
private void downloadFile(final String url){
mExecutorService.submit(new Runnable() {
@Override
public void run() {
Bitmap b = BitmapFromURL.getBitmapFromURL(url);
synchronized (this){
TaskCount--;
}
Intent i = new Intent(ACTION_ON_GET_IMAGE);
ImageBox.mQ.offer(b);
sendBroadcast(i);
if(TaskCount<=0)stopSelf();
}
});
}
My BroadcastReceiver
我BroadcastReceiver
private final BroadcastReceiver mReceiver = new BroadcastReceiver() {
public void onReceive(Context context, Intent intent) {
LOG.d(TAG, "BroadcastReceiver get broadcast");
String action = intent.getAction();
if (DownLoadImageService.ACTION_ON_GET_IMAGE.equals(action)) {
Bitmap b = ImageBox.mQ.poll();
if(b==null)return;
if(mListener!=null)mListener.OnGetImage(b);
}
}
};
#6
0
It might be late but can help. On the first fragment or activity do declare a class...for example
可能会晚些,但会有所帮助。在第一个片段或活动中,请声明一个类……例如
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
description des = new description();
if (requestCode == PICK_IMAGE_REQUEST && data != null && data.getData() != null) {
filePath = data.getData();
try {
bitmap = MediaStore.Images.Media.getBitmap(getActivity().getContentResolver(), filePath);
imageView.setImageBitmap(bitmap);
ByteArrayOutputStream stream = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.PNG, 100, stream);
constan.photoMap = bitmap;
} catch (IOException e) {
e.printStackTrace();
}
}
}
public static class constan {
public static Bitmap photoMap = null;
public static String namePass = null;
}
Then on the second class/fragment do this..
然后在第二类/片段中做这个。
Bitmap bm = postFragment.constan.photoMap;
final String itemName = postFragment.constan.namePass;
Hope it helps.
希望它可以帮助。
#7
0
You can create a bitmap transfer. try this....
您可以创建位图传输。试试这个....
In the first class:
在第一节课:
1) Create:
1)创建:
private static Bitmap bitmap_transfer;
2) Create getter and setter
2)创建getter和setter
public static Bitmap getBitmap_transfer() {
return bitmap_transfer;
}
public static void setBitmap_transfer(Bitmap bitmap_transfer_param) {
bitmap_transfer = bitmap_transfer_param;
}
3) Set the image:
3)设置图片:
ImageView image = (ImageView) view.findViewById(R.id.image);
image.buildDrawingCache();
setBitmap_transfer(image.getDrawingCache());
Then, in the second class:
然后,在第二节课:
ImageView image2 = (ImageView) view.findViewById(R.id.img2);
imagem2.setImageDrawable(new BitmapDrawable(getResources(), classe1.getBitmap_transfer()));
#8
-2
In my case, the way mentioned above didn't worked for me. Every time I put the bitmap in the intent, the 2nd activity didn't start. The same happened when I passed the bitmap as byte[].
就我而言,上面提到的方法对我不起作用。每次我把位图放在意图中,第二个活动就没有开始。当我以byte[]传递位图时,也发生了同样的情况。
I followed this link and it worked like a charme and very fast:
我沿着这个链接,它就像一个魔术,非常快:
package your.packagename
import android.graphics.Bitmap;
public class CommonResources {
public static Bitmap photoFinishBitmap = null;
}
in my 1st acitiviy:
在我acitiviy 1:
Constants.photoFinishBitmap = photoFinishBitmap;
Intent intent = new Intent(mContext, ImageViewerActivity.class);
startActivity(intent);
and here is the onCreate() of my 2nd Activity:
这是我的第二个活动onCreate()
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
Bitmap photo = Constants.photoFinishBitmap;
if (photo != null) {
mViewHolder.imageViewerImage.setImageDrawable(new BitmapDrawable(getResources(), photo));
}
}
#1
261
Bitmap
implements Parcelable
, so you could always pass it with the intent:
位图实现了可分割性,所以您总是可以传递它的意图:
Intent intent = new Intent(this, NewActivity.class);
intent.putExtra("BitmapImage", bitmap);
and retrieve it on the other end:
并在另一端检索:
Intent intent = getIntent();
Bitmap bitmap = (Bitmap) intent.getParcelableExtra("BitmapImage");
#2
19
Actually, passing a bitmap as a Parcelable will result in a "JAVA BINDER FAILURE" error. Try passing the bitmap as a byte array and building it for display in the next activity.
实际上,将位图作为可分配的传递将导致“JAVA绑定失败”错误。尝试将位图作为字节数组传递,并构建它以便在下一个活动中显示。
I shared my solution here:
how do you pass images (bitmaps) between android activities using bundles?
我在这里分享了我的解决方案:如何使用bundle在android活动之间传递图像(位图)?
#3
8
Passsing bitmap as parceable in bundle between activity is not a good idea because of size limitation of Parceable(1mb). You can store the bitmap in a file in internal storage and retrieve the stored bitmap in several activities. Here's some sample code.
由于parceable (1mb)的大小限制,在活动之间将位图作为分组进行分组传递不是一个好主意。您可以在内部存储的文件中存储位图,并在多个活动中检索存储的位图。这里有一些示例代码。
To store bitmap in a file myImage in internal storage:
将位图存储在内部存储的myfile映像中:
public String createImageFromBitmap(Bitmap bitmap) {
String fileName = "myImage";//no .png or .jpg needed
try {
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
FileOutputStream fo = openFileOutput(fileName, Context.MODE_PRIVATE);
fo.write(bytes.toByteArray());
// remember close file output
fo.close();
} catch (Exception e) {
e.printStackTrace();
fileName = null;
}
return fileName;
}
Then in the next activity you can decode this file myImage to a bitmap using following code:
然后在下一个活动中,您可以使用以下代码将这个文件myImage解码到位图:
Bitmap bitmap = BitmapFactory.decodeStream(context
.openFileInput("myImage"));//here context can be anything like getActivity() for fragment, this or MainActivity.this
Note A lot of checking for null and scaling bitmap's is ommited.
注意,很多对null和缩放位图的检查都被省略了。
#4
4
If the image is too large and you can't save&load it to the storage, you should consider just using a global static reference to the bitmap (inside the receiving activity), which will be reset to null on onDestory, only if "isChangingConfigurations" returns true.
如果图像太大,无法保存并加载到存储中,您应该考虑使用位图的全局静态引用(在接收活动中),只有当“isChangingConfigurations”返回true时,该位图将在onDestory上重置为null。
#5
3
Because Intent has size limit . I use public static object to do pass bitmap from service to broadcast ....
因为意图有大小限制。我使用公共静态对象通过位图从服务广播....
public class ImageBox {
public static Queue<Bitmap> mQ = new LinkedBlockingQueue<Bitmap>();
}
pass in my service
通过我的服务
private void downloadFile(final String url){
mExecutorService.submit(new Runnable() {
@Override
public void run() {
Bitmap b = BitmapFromURL.getBitmapFromURL(url);
synchronized (this){
TaskCount--;
}
Intent i = new Intent(ACTION_ON_GET_IMAGE);
ImageBox.mQ.offer(b);
sendBroadcast(i);
if(TaskCount<=0)stopSelf();
}
});
}
My BroadcastReceiver
我BroadcastReceiver
private final BroadcastReceiver mReceiver = new BroadcastReceiver() {
public void onReceive(Context context, Intent intent) {
LOG.d(TAG, "BroadcastReceiver get broadcast");
String action = intent.getAction();
if (DownLoadImageService.ACTION_ON_GET_IMAGE.equals(action)) {
Bitmap b = ImageBox.mQ.poll();
if(b==null)return;
if(mListener!=null)mListener.OnGetImage(b);
}
}
};
#6
0
It might be late but can help. On the first fragment or activity do declare a class...for example
可能会晚些,但会有所帮助。在第一个片段或活动中,请声明一个类……例如
@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
description des = new description();
if (requestCode == PICK_IMAGE_REQUEST && data != null && data.getData() != null) {
filePath = data.getData();
try {
bitmap = MediaStore.Images.Media.getBitmap(getActivity().getContentResolver(), filePath);
imageView.setImageBitmap(bitmap);
ByteArrayOutputStream stream = new ByteArrayOutputStream();
bitmap.compress(Bitmap.CompressFormat.PNG, 100, stream);
constan.photoMap = bitmap;
} catch (IOException e) {
e.printStackTrace();
}
}
}
public static class constan {
public static Bitmap photoMap = null;
public static String namePass = null;
}
Then on the second class/fragment do this..
然后在第二类/片段中做这个。
Bitmap bm = postFragment.constan.photoMap;
final String itemName = postFragment.constan.namePass;
Hope it helps.
希望它可以帮助。
#7
0
You can create a bitmap transfer. try this....
您可以创建位图传输。试试这个....
In the first class:
在第一节课:
1) Create:
1)创建:
private static Bitmap bitmap_transfer;
2) Create getter and setter
2)创建getter和setter
public static Bitmap getBitmap_transfer() {
return bitmap_transfer;
}
public static void setBitmap_transfer(Bitmap bitmap_transfer_param) {
bitmap_transfer = bitmap_transfer_param;
}
3) Set the image:
3)设置图片:
ImageView image = (ImageView) view.findViewById(R.id.image);
image.buildDrawingCache();
setBitmap_transfer(image.getDrawingCache());
Then, in the second class:
然后,在第二节课:
ImageView image2 = (ImageView) view.findViewById(R.id.img2);
imagem2.setImageDrawable(new BitmapDrawable(getResources(), classe1.getBitmap_transfer()));
#8
-2
In my case, the way mentioned above didn't worked for me. Every time I put the bitmap in the intent, the 2nd activity didn't start. The same happened when I passed the bitmap as byte[].
就我而言,上面提到的方法对我不起作用。每次我把位图放在意图中,第二个活动就没有开始。当我以byte[]传递位图时,也发生了同样的情况。
I followed this link and it worked like a charme and very fast:
我沿着这个链接,它就像一个魔术,非常快:
package your.packagename
import android.graphics.Bitmap;
public class CommonResources {
public static Bitmap photoFinishBitmap = null;
}
in my 1st acitiviy:
在我acitiviy 1:
Constants.photoFinishBitmap = photoFinishBitmap;
Intent intent = new Intent(mContext, ImageViewerActivity.class);
startActivity(intent);
and here is the onCreate() of my 2nd Activity:
这是我的第二个活动onCreate()
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
Bitmap photo = Constants.photoFinishBitmap;
if (photo != null) {
mViewHolder.imageViewerImage.setImageDrawable(new BitmapDrawable(getResources(), photo));
}
}