[RxJS] Transformation operators: delay and delayWhen

时间:2022-08-22 14:18:50

This lessons teaches about delay and delayWhen: simple operators that time shift.

delay(number | date)

var foo = Rx.Observable.interval(500).take(5);

/*
--0--1--2--3--4|
delay(1000)
-----0--1--2--3--4|
*/ // delay(1000)
var result = foo.delay(1000); result.subscribe(
function (x) { console.log('next ' + x); },
function (err) { console.log('error ' + err); },
function () { console.log('done'); },
);
var foo = Rx.Observable.interval(500).take(5);

/*
--0--1--2--3--4|
delay(date)
-----0--1--2--3--4|
*/ var date = new Date(new Date().getTime() + 1000);
var result = foo.delay(date); result.subscribe(
function (x) { console.log('next ' + x); },
function (err) { console.log('error ' + err); },
function () { console.log('done'); },
);

delayWhen( function :Observable): accept a function which return an observable:

var foo = Rx.Observable.interval(500).take(5);

/*
--0--1--2--3--4|
delayWhen(x => --------0--------...)
--------0--------1--------2--------3--------4|
*/ // delay(1000)
var result = foo.delayWhen(x =>
Rx.Observable.interval(x * 1000) // For each foo, it will delay 1000 * x, so '2' --> 2000, '3' ---> 3000
); result.subscribe(
function (x) { console.log('next ' + x); },
function (err) { console.log('error ' + err); },
function () { console.log('done'); },
);