How do you convert a Unix timestamp (seconds since epoch) to Ruby DateTime?
如何将一个Unix时间戳(自epoch以来的秒)转换为Ruby DateTime?
6 个解决方案
#1
277
DateTime.strptime can handle seconds since epoch. The number must be converted to a string:
DateTime。strptime可以处理自epoch以来的秒数。数字必须转换为字符串:
require 'date'
DateTime.strptime("1318996912",'%s')
#2
551
Sorry, brief moment of synapse failure. Here's the real answer.
抱歉，是synapse失败的短暂瞬间。这是真正的答案。
require 'date'
Time.at(seconds_since_epoch_integer).to_datetime
Brief example (this takes into account the current system timezone):
简单示例(考虑到当前系统时区):
$ date +%s
1318996912
$ irb
ruby-1.9.2-p180 :001 > require 'date'
=> true
ruby-1.9.2-p180 :002 > Time.at(1318996912).to_datetime
=> #<DateTime: 2011-10-18T23:01:52-05:00 (13261609807/5400,-5/24,2299161)>
Further update (for UTC):
进一步更新(UTC):
ruby-1.9.2-p180 :003 > Time.at(1318996912).utc.to_datetime
=> #<DateTime: 2011-10-19T04:01:52+00:00 (13261609807/5400,0/1,2299161)>
Recent Update: I benchmarked the top solutions in this thread while working on a HA service a week or two ago, and was surprised to find that Time.at(..) outperforms DateTime.strptime(..) (update: added more benchmarks).
最近的更新:我在一两个星期前处理HA服务的时候，在这个线程中对顶部的解决方案进行了基准测试，并且很惊讶地发现Time.at(..)超过了DateTime.strptime(..)(更新:添加了更多的基准)。
# ~ % ruby -v
# => ruby 2.1.5p273 (2014-11-13 revision 48405) [x86_64-darwin13.0]
irb(main):038:0> Benchmark.measure do
irb(main):039:1* ["1318996912", "1318496912"].each do |s|
irb(main):040:2* DateTime.strptime(s, '%s')
irb(main):041:2> end
irb(main):042:1> end
=> #<Benchmark ... @real=2.9e-05 ... @total=0.0>
irb(main):044:0> Benchmark.measure do
irb(main):045:1> [1318996912, 1318496912].each do |i|
irb(main):046:2> DateTime.strptime(i.to_s, '%s')
irb(main):047:2> end
irb(main):048:1> end
=> #<Benchmark ... @real=2.0e-05 ... @total=0.0>
irb(main):050:0* Benchmark.measure do
irb(main):051:1* ["1318996912", "1318496912"].each do |s|
irb(main):052:2* Time.at(s.to_i).to_datetime
irb(main):053:2> end
irb(main):054:1> end
=> #<Benchmark ... @real=1.5e-05 ... @total=0.0>
irb(main):056:0* Benchmark.measure do
irb(main):057:1* [1318996912, 1318496912].each do |i|
irb(main):058:2* Time.at(i).to_datetime
irb(main):059:2> end
irb(main):060:1> end
=> #<Benchmark ... @real=2.0e-05 ... @total=0.0>
#3
38
Time Zone Handling
时区处理
I just want to clarify, even though this has been commented so future people don't miss this very important distinction.
我只是想澄清一下，尽管这已经被评论过了，所以未来的人们不会错过这个非常重要的区别。
DateTime.strptime("1318996912",'%s') # => Wed, 19 Oct 2011 04:01:52 +0000
displays a return value in UTC and requires the seconds to be a String and outputs a UTC Time object, whereas
在UTC中显示返回值，并要求秒为字符串并输出UTC时间对象，而。
Time.at(1318996912) # => 2011-10-19 00:01:52 -0400
displays a return value in the LOCAL time zone, normally requires a FixNum argument, but the Time object itself is still in UTC even though the display is not.
在本地时区中显示一个返回值，通常需要一个FixNum参数，但是时间对象本身仍然在UTC中，即使显示不是。
So even though I passed the same integer to both methods, I seemingly two different results because of how the class' #to_s method works. However, as @Eero had to remind me twice of:
因此，即使我将相同的整数传递给了这两种方法，但由于类的#to_s方法的工作方式，我似乎得到了两个不同的结果。然而，@Eero不得不提醒我两次:
Time.at(1318996912) == DateTime.strptime("1318996912",'%s') # => true
An equality comparison between the two return values still returns true. Again, this is because the values are basically the same (although different class's, the #== method takes care of this for you), but the #to_s method prints drastically different strings. Although, if we look at the strings, we can see they are indeed the same time, just printed in different time zones.
两个返回值之间的相等比较仍然返回true。同样，这是因为这些值基本上是相同的(尽管不同的类，#==方法为您处理了这个问题)，但是#to_s方法打印了截然不同的字符串。尽管，如果我们看一下字符串，我们可以看到它们确实是同时出现的，只是在不同的时区里打印出来的。
Method Argument Clarification
方法参数说明
The docs also say "If a numeric argument is given, the result is in local time." which makes sense, but was a little confusing to me because they don't give any examples of non-integer arguments in the docs. So, for some non-integer argument examples:
文档还说“如果给出了一个数字参数，结果是在本地时间。”这是有意义的，但对我来说有点困惑，因为他们没有给出文档中任何非整数参数的例子。对于一些非整数的参数例子:
Time.at("1318996912")
TypeError: can't convert String into an exact number
you can't use a String argument, but you can use a Time argument into Time.at and it will return the result in the time zone of the argument:
您不能使用字符串参数，但是可以将时间参数用于时间。它将在参数的时区返回结果:
Time.at(Time.new(2007,11,1,15,25,0, "+09:00"))
=> 2007-11-01 15:25:00 +0900
****edited to not be completely and totally incorrect in every way****
***编辑的内容不完全，完全不正确****。
#4
6
One command to convert date time to Unix format and then to string
一个命令将日期时间转换为Unix格式，然后转换为字符串。
DateTime.strptime(Time.now.utc.to_i.to_s,'%s').strftime("%d %m %y")
Time.now.utc.to_i #Converts time from Unix format
DateTime.strptime(Time.now.utc.to_i.to_s,'%s') #Converts date and time from unix format to DateTime
finally strftime is used to format date
最后，strftime用于格式化日期。
Example:
例子:
irb(main):034:0> DateTime.strptime("1410321600",'%s').strftime("%d %m %y")
"10 09 14"
#5
1
This tells you the date of the number of seconds in future from the moment you execute the code.
这将告诉您从执行代码的那一刻起，未来的秒数。
time = Time.new + 1000000000 #date in 1 billion seconds
puts(time)
把(时间)
according to the current time I am answering the question it prints 047-05-14 05:16:16 +0000 (1 billion seconds in future)
根据当前时间，我正在回答它打印的问题047-05-14 05:16:16 +0000(未来10亿秒)
or if you want to count billion seconds from a particular time, it's in format Time.mktime(year, month,date,hours,minutes)
或者如果你想从特定的时间计算出十亿秒，那就是格式时间。mktime(年、月、日、小时、分钟)
time = Time.mktime(1987,8,18,6,45) + 1000000000
puts("I would be 1 Billion seconds old on: "+time)
put(“我将有10亿秒的时间:”+time)
#6
0
If you wanted just a Date, you can do Date.strptime(invoice.date.to_s, '%s') where invoice.date comes in the form of anFixnum and then converted to a String.
如果您想要一个日期，您可以做日期。strptime(invoice.date)。to_s ' % s '),发票。日期以anFixnum的形式出现，然后转换为字符串。
#1
277
DateTime.strptime can handle seconds since epoch. The number must be converted to a string:
DateTime。strptime可以处理自epoch以来的秒数。数字必须转换为字符串:
require 'date'
DateTime.strptime("1318996912",'%s')
#2
551
Sorry, brief moment of synapse failure. Here's the real answer.
抱歉，是synapse失败的短暂瞬间。这是真正的答案。
require 'date'
Time.at(seconds_since_epoch_integer).to_datetime
Brief example (this takes into account the current system timezone):
简单示例(考虑到当前系统时区):
$ date +%s
1318996912
$ irb
ruby-1.9.2-p180 :001 > require 'date'
=> true
ruby-1.9.2-p180 :002 > Time.at(1318996912).to_datetime
=> #<DateTime: 2011-10-18T23:01:52-05:00 (13261609807/5400,-5/24,2299161)>
Further update (for UTC):
进一步更新(UTC):
ruby-1.9.2-p180 :003 > Time.at(1318996912).utc.to_datetime
=> #<DateTime: 2011-10-19T04:01:52+00:00 (13261609807/5400,0/1,2299161)>
Recent Update: I benchmarked the top solutions in this thread while working on a HA service a week or two ago, and was surprised to find that Time.at(..) outperforms DateTime.strptime(..) (update: added more benchmarks).
最近的更新:我在一两个星期前处理HA服务的时候，在这个线程中对顶部的解决方案进行了基准测试，并且很惊讶地发现Time.at(..)超过了DateTime.strptime(..)(更新:添加了更多的基准)。
# ~ % ruby -v
# => ruby 2.1.5p273 (2014-11-13 revision 48405) [x86_64-darwin13.0]
irb(main):038:0> Benchmark.measure do
irb(main):039:1* ["1318996912", "1318496912"].each do |s|
irb(main):040:2* DateTime.strptime(s, '%s')
irb(main):041:2> end
irb(main):042:1> end
=> #<Benchmark ... @real=2.9e-05 ... @total=0.0>
irb(main):044:0> Benchmark.measure do
irb(main):045:1> [1318996912, 1318496912].each do |i|
irb(main):046:2> DateTime.strptime(i.to_s, '%s')
irb(main):047:2> end
irb(main):048:1> end
=> #<Benchmark ... @real=2.0e-05 ... @total=0.0>
irb(main):050:0* Benchmark.measure do
irb(main):051:1* ["1318996912", "1318496912"].each do |s|
irb(main):052:2* Time.at(s.to_i).to_datetime
irb(main):053:2> end
irb(main):054:1> end
=> #<Benchmark ... @real=1.5e-05 ... @total=0.0>
irb(main):056:0* Benchmark.measure do
irb(main):057:1* [1318996912, 1318496912].each do |i|
irb(main):058:2* Time.at(i).to_datetime
irb(main):059:2> end
irb(main):060:1> end
=> #<Benchmark ... @real=2.0e-05 ... @total=0.0>
#3
38
Time Zone Handling
时区处理
I just want to clarify, even though this has been commented so future people don't miss this very important distinction.
我只是想澄清一下，尽管这已经被评论过了，所以未来的人们不会错过这个非常重要的区别。
DateTime.strptime("1318996912",'%s') # => Wed, 19 Oct 2011 04:01:52 +0000
displays a return value in UTC and requires the seconds to be a String and outputs a UTC Time object, whereas
在UTC中显示返回值，并要求秒为字符串并输出UTC时间对象，而。
Time.at(1318996912) # => 2011-10-19 00:01:52 -0400
displays a return value in the LOCAL time zone, normally requires a FixNum argument, but the Time object itself is still in UTC even though the display is not.
在本地时区中显示一个返回值，通常需要一个FixNum参数，但是时间对象本身仍然在UTC中，即使显示不是。
So even though I passed the same integer to both methods, I seemingly two different results because of how the class' #to_s method works. However, as @Eero had to remind me twice of:
因此，即使我将相同的整数传递给了这两种方法，但由于类的#to_s方法的工作方式，我似乎得到了两个不同的结果。然而，@Eero不得不提醒我两次:
Time.at(1318996912) == DateTime.strptime("1318996912",'%s') # => true
An equality comparison between the two return values still returns true. Again, this is because the values are basically the same (although different class's, the #== method takes care of this for you), but the #to_s method prints drastically different strings. Although, if we look at the strings, we can see they are indeed the same time, just printed in different time zones.
两个返回值之间的相等比较仍然返回true。同样，这是因为这些值基本上是相同的(尽管不同的类，#==方法为您处理了这个问题)，但是#to_s方法打印了截然不同的字符串。尽管，如果我们看一下字符串，我们可以看到它们确实是同时出现的，只是在不同的时区里打印出来的。
Method Argument Clarification
方法参数说明
The docs also say "If a numeric argument is given, the result is in local time." which makes sense, but was a little confusing to me because they don't give any examples of non-integer arguments in the docs. So, for some non-integer argument examples:
文档还说“如果给出了一个数字参数，结果是在本地时间。”这是有意义的，但对我来说有点困惑，因为他们没有给出文档中任何非整数参数的例子。对于一些非整数的参数例子:
Time.at("1318996912")
TypeError: can't convert String into an exact number
you can't use a String argument, but you can use a Time argument into Time.at and it will return the result in the time zone of the argument:
您不能使用字符串参数，但是可以将时间参数用于时间。它将在参数的时区返回结果:
Time.at(Time.new(2007,11,1,15,25,0, "+09:00"))
=> 2007-11-01 15:25:00 +0900
****edited to not be completely and totally incorrect in every way****
***编辑的内容不完全，完全不正确****。
#4
6
One command to convert date time to Unix format and then to string
一个命令将日期时间转换为Unix格式，然后转换为字符串。
DateTime.strptime(Time.now.utc.to_i.to_s,'%s').strftime("%d %m %y")
Time.now.utc.to_i #Converts time from Unix format
DateTime.strptime(Time.now.utc.to_i.to_s,'%s') #Converts date and time from unix format to DateTime
finally strftime is used to format date
最后，strftime用于格式化日期。
Example:
例子:
irb(main):034:0> DateTime.strptime("1410321600",'%s').strftime("%d %m %y")
"10 09 14"
#5
1
This tells you the date of the number of seconds in future from the moment you execute the code.
这将告诉您从执行代码的那一刻起，未来的秒数。
time = Time.new + 1000000000 #date in 1 billion seconds
puts(time)
把(时间)
according to the current time I am answering the question it prints 047-05-14 05:16:16 +0000 (1 billion seconds in future)
根据当前时间，我正在回答它打印的问题047-05-14 05:16:16 +0000(未来10亿秒)
or if you want to count billion seconds from a particular time, it's in format Time.mktime(year, month,date,hours,minutes)
或者如果你想从特定的时间计算出十亿秒，那就是格式时间。mktime(年、月、日、小时、分钟)
time = Time.mktime(1987,8,18,6,45) + 1000000000
puts("I would be 1 Billion seconds old on: "+time)
put(“我将有10亿秒的时间:”+time)
#6
0
If you wanted just a Date, you can do Date.strptime(invoice.date.to_s, '%s') where invoice.date comes in the form of anFixnum and then converted to a String.
如果您想要一个日期，您可以做日期。strptime(invoice.date)。to_s ' % s '),发票。日期以anFixnum的形式出现，然后转换为字符串。