hdu 1034 (preprocess optimization, property of division to avoid if, decreasing order process) 分类: hdoj 2015-06-16 13:32 39人阅读 评论(0) 收藏

时间:2023-03-09 00:59:10
hdu 1034 (preprocess optimization, property of division to avoid if, decreasing order process)                                                       分类:            hdoj             2015-06-16 13:32    39人阅读    评论(0)    收藏

IMO, version 1 better than version 2, version 2 better than version 3.

make some preprocess to make you code simple and efficient. Here divide the input by 2, so you don’t have to do dividsion on each loop.

version 1 is best

thanks to

http://www.cnblogs.com/kuangbin/archive/2012/06/03/2532690.html

#include <cstdio>
#include <algorithm> #define MAXSIZE 10000 int candies[MAXSIZE]; int main() {
//freopen("input.txt","r",stdin);
int n, cnt_whistle, i, tmp;
while(scanf("%d",&n)!=EOF && n>0) {
for(i=0;i<n;++i) { scanf("%d",&tmp); candies[i]=tmp>>1; }
for(--n, cnt_whistle=1;;++cnt_whistle) {
tmp=candies[n];
for(i=n;i>0;--i) {
candies[i]=(candies[i-1]+candies[i]+1)>>1;
}
candies[0]=(tmp+candies[0]+1)>>1;
for(i=1;i<=n && candies[i-1]==candies[i];++i) ;
if(i-n==1) break;
}
printf("%d %d\n",cnt_whistle,candies[0]<<1);
}
return 0;
}

use division’s floor property (5/2=2) to avoid if sentences. in version 2 here

t2=candies[i];
candies[i]=(t1+t2+1)>>1;
t1=t2;

if don’t divide input by 2, the code will be

t2=candies[i]>>1;
candies[i]=t1+t2;
if(candies[i]%2) ++candies[i];
t1=t2;

how to avoid process the border conditions? version 2 better than version 3 on this aspect. version 1 accomplish this, thanks to

http://www.acmerblog.com/hdu-1034-candy-sharing-game-1285.html

version 2

#include <cstdio>
#include <algorithm> #define MAXSIZE 10000 int candies[MAXSIZE]; int main() {
//freopen("input.txt","r",stdin);
int n, cnt_whistle, i, t1,t2;
while(scanf("%d",&n)!=EOF && n>0) {
for(i=0;i<n;++i) { scanf("%d",&t1); candies[i]=t1>>1; }
for(--n, cnt_whistle=1;;++cnt_whistle) {
t1=candies[n];
for(i=0;i<=n;++i) {
t2=candies[i];
candies[i]=(t1+candies[i]+1)>>1;
t1=t2;
}
for(i=1;i<=n && candies[i-1]==candies[i];++i) ;
if(i-n==1) break;
}
printf("%d %d\n",cnt_whistle,candies[0]<<1);
}
return 0;
}

version 3

#include <cstdio>
#include <algorithm> #define MAXSIZE 10000 int candies[MAXSIZE];
int cand_temp[MAXSIZE]; int main() {
//freopen("input.txt","r",stdin);
int n, cnt_whistle, i, *p,*q;
while(scanf("%d",&n)!=EOF && n>0) {
for(i=0;i<n;++i) { scanf("%d",&t1); candies[i]=t1>>1; }
p=candies, q=cand_temp;
for(--n, cnt_whistle=1;;++cnt_whistle) {
for(i=1;i<=n;++i) {
q[i]=(p[i-1]+p[i]+1)>>1;
}
q[0]=(p[n]+p[0]+1)>>1;
std::swap(p,q);
for(i=1;i<=n && p[i-1]==p[i];++i) ;
if(i-n==1) break;
}
printf("%d %d\n",cnt_whistle,p[0]<<1);
}
return 0;
}

p.s. when you use swap tricks (as in version 3), be careful with the check points, e.g. the initialization part, the conclusion part, especially the items are used by multiple times.

here is mistake I made, 1st, initilization error

position of

cnt_whistle=1;

mistakely put it to declaration part rather than just befor the for loop;

2nd, the third parameter of printf

mistakely wirite

printf("%d %d\n",cnt_whistle,candies[0]<<1);

which should be

printf("%d %d\n",cnt_whistle,p[0]<<1);

版权声明:本文为博主原创文章,未经博主允许不得转载。// p.s. If in any way improment can be achieved, better performance or whatever, it will be well-appreciated to let me know, thanks in advance.