python数据结构之二叉树的统计与转换实例

时间:2023-03-09 04:45:07
python数据结构之二叉树的统计与转换实例

python数据结构之二叉树的统计与转换实例

这篇文章主要介绍了python数据结构之二叉树的统计与转换实例,例如统计二叉树的叶子、分支节点,以及二叉树的左右两树互换等,需要的朋友可以参考下

一、获取二叉树的深度



就是二叉树最后的层次,如下图:

python数据结构之二叉树的统计与转换实例

实现代码:

代码如下:



def getheight(self):

       
''' 获取二叉树深度 '''

       
return self.__get_tree_height(self.root)



    def
__get_tree_height(self, root):

       
if root is 0:

           
return 0

       
if root.left is 0 and root.right is 0:

           
return 1

       
else:

           
left = self.__get_tree_height(root.left)

           
right = self.__get_tree_height(root.right)

           
if left < right:

               
return right 1

           
else:

               
return left 1



二、叶子的统计



叶子就是二叉树的节点的 left 指针和 right 指针分别指向空的节点

复制代码 代码如下:



def getleafcount(self):

       
''' 获取二叉树叶子数 '''

       
return self.__count_leaf_node(self.root)



    def
__count_leaf_node(self, root):

       
res = 0

       
if root is 0:

           
return res

       
if root.left is 0 and root.right is 0:

           
res = 1

           
return res

       
if root.left is not 0:

           
res = self.__count_leaf_node(root.left)

       
if root.right is not 0:

           
res = self.__count_leaf_node(root.right)

       
return res



三、统计叶子的分支节点



与叶子节点相对的其他节点 left 和 right 的指针指向其他节点



复制代码 代码如下:



def getbranchcount(self):

       
''' 获取二叉树分支节点数 '''

       
return self.__get_branch_node(self.root)



    def
__get_branch_node(self, root):

       
if root is 0:

           
return 0

       
if root.left is 0 and root.right is 0:

           
return 0

       
else:

           
return 1 self.__get_branch_node(root.left)
self.__get_branch_node(root.right)



四、二叉树左右树互换



代码如下:



def replacelem(self):

       
''' 二叉树所有结点的左右子树相互交换 '''

       
self.__replace_element(self.root)



    def
__replace_element(self, root):

       
if root is 0:

           
return

       
root.left, root.right = root.right, root.left

       
self.__replace_element(root.left)

       
self.__replace_element(root.right)

这些方法和操作,都是运用递归。其实二叉树的定义也是一种递归。附上最后的完整代码:

代码如下:



# -*- coding: utf - 8 - *-



    

class TreeNode(object):



    def
__init__(self, left=0, right=0, data=0):

       
self.left = left

       
self.right = right

       
self.data = data



    

class BinaryTree(object):



    def
__init__(self, root=0):

       
self.root = root



    def
is_empty(self):

       
if self.root is 0:

           
return True

       
else:

           
return False



    def
create(self):

       
temp = input('enter a value:')

       
if temp is '#':

           
return 0

       
treenode = TreeNode(data=temp)

       
if self.root is 0:

           
self.root = treenode



       
treenode.left = self.create()

       
treenode.right = self.create()



    def
preorder(self, treenode):

       
'前序(pre-order,NLR)遍历'

       
if treenode is 0:

           
return

       
print treenode.data

       
self.preorder(treenode.left)

       
self.preorder(treenode.right)



    def
inorder(self, treenode):

       
'中序(in-order,LNR'

       
if treenode is 0:

           
return

       
self.inorder(treenode.left)

       
print treenode.data

       
self.inorder(treenode.right)



    def
postorder(self, treenode):

       
'后序(post-order,LRN)遍历'

       
if treenode is 0:

           
return

       
self.postorder(treenode.left)

       
self.postorder(treenode.right)

       
print treenode.data



    def
preorders(self, treenode):

       
'前序(pre-order,NLR)非递归遍历'

       
stack = []

       
while treenode or stack:

           
if treenode is not 0:

               
print treenode.data

               
stack.append(treenode)

               
treenode = treenode.left

           
else:

               
treenode = stack.pop()

               
treenode = treenode.right



    def
inorders(self, treenode):

       
'中序(in-order,LNR) 非递归遍历'

       
stack = []

       
while treenode or stack:

           
if treenode:

               
stack.append(treenode)

               
treenode = treenode.left

           
else:

               
treenode = stack.pop()

               
print treenode.data

               
treenode = treenode.right



    def
postorders(self, treenode):

       
'后序(post-order,LRN)非递归遍历'

       
stack = []

       
pre = 0

       
while treenode or stack:

           
if treenode:

               
stack.append(treenode)

               
treenode = treenode.left

           
elif stack[-1].right != pre:

               
treenode = stack[-1].right

               
pre = 0

           
else:

               
pre = stack.pop()

               
print pre.data



    # def
postorders(self, treenode):

   
#    
'后序(post-order,LRN)非递归遍历'

   
#    
stack = []

   
#    
queue = []

   
#    
queue.append(treenode)

   
#    
while queue:

   
#        
treenode = queue.pop()

   
#        
if treenode.left:

   
#            
queue.append(treenode.left)

   
#        
if treenode.right:

   
#            
queue.append(treenode.right)

   
#        
stack.append(treenode)

   
#    
while stack:

   
#        
print stack.pop().data



    def
levelorders(self, treenode):

       
'层序(post-order,LRN)非递归遍历'

       
from collections import deque

       
if not treenode:

           
return

       
q = deque([treenode])

       
while q:

           
treenode = q.popleft()

           
print treenode.data

           
if treenode.left:

               
q.append(treenode.left)

           
if treenode.right:

               
q.append(treenode.right)



    def
getheight(self):

       
''' 获取二叉树深度 '''

       
return self.__get_tree_height(self.root)



    def
__get_tree_height(self, root):

       
if root is 0:

           
return 0

       
if root.left is 0 and root.right is 0:

           
return 1

       
else:

           
left = self.__get_tree_height(root.left)

           
right = self.__get_tree_height(root.right)

           
if left < right:

               
return right 1

           
else:

               
return left 1



    def
getleafcount(self):

       
''' 获取二叉树叶子数 '''

       
return self.__count_leaf_node(self.root)



    def
__count_leaf_node(self, root):

       
res = 0

       
if root is 0:

           
return res

       
if root.left is 0 and root.right is 0:

           
res = 1

           
return res

       
if root.left is not 0:

           
res = self.__count_leaf_node(root.left)

       
if root.right is not 0:

           
res = self.__count_leaf_node(root.right)

       
return res



    def
getbranchcount(self):

       
''' 获取二叉树分支节点数 '''

       
return self.__get_branch_node(self.root)



    def
__get_branch_node(self, root):

       
if root is 0:

           
return 0

       
if root.left is 0 and root.right is 0:

           
return 0

       
else:

           
return 1 self.__get_branch_node(root.left)
self.__get_branch_node(root.right)



    def
replacelem(self):

       
''' 二叉树所有结点的左右子树相互交换 '''

       
self.__replace_element(self.root)



    def
__replace_element(self, root):

       
if root is 0:

           
return

       
root.left, root.right = root.right, root.left

       
self.__replace_element(root.left)

       
self.__replace_element(root.right)



node1 = TreeNode(data=1)

node2 = TreeNode(node1, 0, 2)

node3 = TreeNode(data=3)

node4 = TreeNode(data=4)

node5 = TreeNode(node3, node4, 5)

node6 = TreeNode(node2, node5, 6)

node7 = TreeNode(node6, 0, 7)

node8 = TreeNode(data=8)

root = TreeNode(node7, node8, 'root')



    

bt = BinaryTree(root)



print u'''



生成的二叉树



------------------------

        
root

     
7       
8

    6

  2   5

1    3 4



-------------------------



'''