Python3.x:访问带参数链接并且获取返回json串

时间:2023-03-09 23:44:47
Python3.x:访问带参数链接并且获取返回json串

Python3.x:访问带参数链接并且获取返回json串

示例一:

import json
import xml.dom.minidom
from urllib import request, parse
from sqlalchemy import func url = "http://**********/queryTradingByProdTypeData.do"
headerDict = {'Host': 'query.sse.com.cn',
'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; Win64; x64; rv:54.0) Gecko/20100101 Firefox/54.0',
'Accept': '*/*', 'Accept-Language': 'zh-CN,zh;q=0.8,en-US;q=0.5,en;q=0.3',
'Accept-Encoding': 'gzip, deflate',
'Referer': 'http://**************/funddata/overview/day/',
'Connection': 'keep-alive'}
jsonName = 'jsonpCallback24028'
data = {'jsonCallBack': jsonName, 'searchDate': dataDate, 'prodType': 'jj'}
params = parse.urlencode(data).encode('utf-8')
req = request.Request(url, headers=headerDict)
page = str(request.urlopen(req, data=params).read(), encoding="utf-8") rdata = page[len(jsonName) + 1:len(page) - 1]
jsondata = json.loads(rdata)
print("json>>:%s" %jsondata)

示例二:

# 获取主要指标概览表
def getChannelIdStr(channelFidStr):
url = "http://www.*****/getSubChannel.action"
headerDict = {'Host': 'www.*****.cn',
'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/61.0.3163.31 Safari/537.36',
'Accept': 'application/json, text/javascript, */*; q=0.01',
'Accept-Language': 'zh-CN,zh;q=0.8',
'Accept-Encoding': 'gzip, deflate',
'Referer': 'http://www.******/monthview.action?action=china',
'Connection': 'keep-alive'}
data = {'channelFidStr': channelFidStr}
# psot 传递参数
res = requests.post(url, data=data, headers=headerDict)
# 获取跳转后的页面源码,返回json串
soup = BeautifulSoup(res.content, "html.parser")
print(soup)
# 转换json格式
jsonArr = json.loads(soup.text)
# 遍历json数组
channelId = []
for jsonStr in jsonArr:
channelId.append(jsonStr['channelId'])
print(jsonStr['channelName'])
return channelId